<?php while($result = mysql_fetch_array( $resulta )) {
echo "<tr>";
echo "\t\t<td>{$result['denumire_locatie']}</td>\n";
echo "\t\t<td>{$result['tip_locatie']}</td>\n";
echo "\t\t<td>{$result['judet']}</td>\n";
echo "\t\t<td>{$result['localitate']}</td>\n";
echo "\t\t<td>{$result['strada']}</td>\n";
echo "\t\t<td>{$result['numar']}</td>\n";
echo "\t\t<td>{$result['telefon']}</td>\n";
echo "\t\t<td>{$result['fax']}</td>\n";
echo "\t\t<td>{$result['email']}</td>\n";
echo "\t\t<td>{$result['descriere']}</td>\n";
echo "\t\t<td><a href="/oferta.php?id={$result['id_oferta']}">click pentru detalii</a></td>\n";
echo "</tr>";
}
When I run I get the following error message: Parse error: syntax error, unexpected '=' in C:\xampp\htdocs\SITE\index.php on line 157 Line 157 is the following one:
echo "\t\t<td><a href="/oferta.php?id={$result['id_oferta']}">click pentru detalii</a></td>\n";
Can anyone see the problem?