validation - Laravel 4 验证唯一（数据库）忽略当前

Question

我正在对用户编辑表单进行验证，并让验证检查用户名在数据库中是否唯一。

但是，当编辑用户并且您不更改用户名字段时，它仍在检查该字段是否是唯一的......

如果没有更改，是否有一种 laravel 方法可以忽略当前用户名？

Answer 1

应该更多地阅读文档，当然 laravel 4 会这样做......

我所拥有的

$rules = array('username' => 'required|unique:users');

我有的

$rules = array('username' => 'required|unique:users,username,'.$id);

您可以告诉验证器忽略上面的给定 ID。

Answer 2

这个解决方案对我有用：

protected  $rules = array(
    'email' => "required|email|unique:users,email,:id",
);

Answer 3

对于 Laravel 4.1，如果你扩展Illuminate\Validation\Validator类，重写validateUnique()方法如下：

/**
 * Validate the uniqueness of an attribute value on a given database table.
 *
 * If a database column is not specified, the attribute will be used.
 *
 * @param  string  $attribute
 * @param  mixed   $value
 * @param  array   $parameters
 * @return bool
 */
protected function validateUnique($attribute, $value, $parameters)
{
    $this->requireParameterCount(1, $parameters, 'unique');

    $table = $parameters[0];

    // The second parameter position holds the name of the column that needs to
    // be verified as unique. If this parameter isn't specified we will just
    // assume that this column to be verified shares the attribute's name.
    $column = isset($parameters[1]) ? $parameters[1] : $attribute;

    // If the specified ID column is present in the data, use those values; otherwise,
    // fall back on supplied parameters.
    list($idColumn, $id) = [null, null];
    if (isset($parameters[2])) {
        list($idColumn, $id) = $this->getUniqueIds($parameters);

        if (strtolower($id) == 'null') $id = null;
        else if (strtolower($id) == 'id' && isset($this->data[$idColumn])) $id = $this->data[$idColumn];
    }
    else if (isset($this->data['id'])) {
        $idColumn = 'id';
        $id = $this->data[$idColumn];
    }

    // The presence verifier is responsible for counting rows within this store
    // mechanism which might be a relational database or any other permanent
    // data store like Redis, etc. We will use it to determine uniqueness.
    $verifier = $this->getPresenceVerifier();

    $extra = $this->getUniqueExtra($parameters);

    return $verifier->getCount(

        $table, $column, $value, $id, $idColumn, $extra

    ) == 0;
}

在您的验证器规则中，您可以这样做（将检查id验证数据中存在的字段 - 这是最通用的用法）：

$rules = 'unique:model,field';

这（将检查id验证数据中存在的字段）（相当于上述）：

// specifying anything other than 'id' or 'null' as the 3rd parameter
// will still use the current behavior
$rules = 'unique:model,field,id'; 

或者这个（将检查idColumn验证数据中存在的字段）：

// specifying anything other than 'id' or 'null' as the 3rd parameter
// will still use the current behavior
$rules = 'unique:model,field,id,idColumn';

Answer 4

嗨，您可以将验证器用作服务或复制逻辑并应用您的需要，就像这样

$valitator = MyCustomValidator::make()->on('update')->setCurrent($id); 

签到： https ://github.com/bradleySuira/laravel-context-validator/blob/master/examples/unique-on-update.php