1

我们在 SQL Server 2008 R2 中有 2 个表。周期性地,我们必须将一批记录从表 A 插入到表 B。在插入时,表 B 仍然能够 SELECT & UPDATE。目前,我们使用 INSERT..SELECT 从表 A 复制到表 B。但问题是在插入时,有时会导致 UPDATE 语句对表 B 超时。

有没有更好的从一个表到另一个不会导致阻塞的批量插入解决方案?

4

2 回答 2

0

他们最明显的解决方案是按照斯坦利的建议使用较小的批次。如果这真的不是一个选项,您可以探索' (事务级别)快照隔离

于 2013-06-07T04:02:10.297 回答
0

1 将事务超时设置为足够大的值,以使语句不再超时。

2 使用 CURSOR 并逐行执行

3 试试这种做事方式。需要一个行标识符(例如 IDENTITY),最好在该字段上有一个 PK 或 INDEX:

SET NOCOUNT ON;

CREATE TABLE #A(
    row_id INT IDENTITY(1,1) NOT NULL PRIMARY KEY,
    data INT NOT NULL
);

CREATE TABLE #B(
    row_id INT NOT NULL PRIMARY KEY,
    data INT NOT NULL
);

-- TRUNCATE TABLE #B; -- no truncate needed since you just want to add rows, not copy the whole table

DECLARE @batch_size INT;
SET @batch_size = 10000;

DECLARE @from_row_id INT;
DECLARE @to_row_id INT;

-- You would use this to establish the first @from_row_id if you wanted to copy the whole table
-- SELECT
--   @from_row_id=ISNULL(MIN(row_id),-1)
-- FROM
--   #A AS a;

SELECT
    @from_row_id=ISNULL(MAX(row_id),-1)
FROM
    #B AS b;

IF @from_row_id=-1
    SELECT
        @from_row_id=ISNULL(MIN(row_id),-1)
    FROM
        #A AS a;
ELSE
    SELECT
        @from_row_id=ISNULL(MIN(row_id),-1)
    FROM
        #A AS a
    WHERE
        row_id>@from_row_id;

WHILE @from_row_id>=0
BEGIN
    SELECT
        @to_row_id=ISNULL(MAX(row_id),-1)
    FROM
        (
            SELECT TOP(@batch_size)
                row_id
            FROM
                #A AS a
            WHERE
                row_id>=@from_row_id
        ) AS row_ids

    IF @to_row_id=-1
    BEGIN
        INSERT 
            #B
        SELECT
            *
        FROM
            #A AS a
        WHERE
            row_id>=@from_row_id;

        BREAK;
    END
    ELSE
        INSERT 
            #B
        SELECT
            *
        FROM
            #A AS a
        WHERE
            row_id BETWEEN @from_row_id AND @to_row_id;

    SELECT
        @from_row_id=ISNULL(MIN(row_id),-1)
    FROM
        #A AS a
    WHERE
        row_id>@to_row_id;
END 

DROP TABLE #B;
DROP TABLE #A;
于 2013-06-07T03:47:55.667 回答