1

在发送我的 JSON 响应时，我以可见的形式显示内容类型。这是一个问题，因为当我在另一端解析 JSON 时，它包含标头并且无法解析回哈希图。

我应该如何编码这个响应，以便标题不会“显示”

这是生成响应的方法

/**
     * Sends reply back to client
     * @throws Exception
     */
    private void sendResponse() throws Exception{

        //Content type
        String contentTypeLine = "Content-Type: text/json" + "\r\n";

        //Create dummy JSON object
        HashMap<String, String> mapResponse = new HashMap<String, String>();
        mapResponse.put("Author", "James");
        mapResponse.put("Author 2", "John");

        //Convert to JSON
        Gson gson = new Gson();
        String json = gson.toJson(mapResponse);

        //Set type
        responseToClient.writeBytes(contentTypeLine);

        //Set JSON
        responseToClient.writeBytes(json);

    }

这是示例响应

Content-Type: text/json
{"Author":"James","Author 2":"John"}

请求获取代码

/**
     * Code to execute on thread
     */
    public void run(){

        try {

            //Log new client
            System.out.println("The client " + connectedClient.getInetAddress() + 
                    ":" + connectedClient.getPort() + " is connected");

            //Get the client request
            clientRequest = new BufferedReader(new InputStreamReader(connectedClient.getInputStream()));

            //Start response object
            responseToClient = new DataOutputStream(connectedClient.getOutputStream());

            //Process the request
            processClientRequest();

            //Close buffered writer
            responseToClient.close();
        } catch (Exception e) {

            //Print error
            e.printStackTrace();
        }
    }

谢谢！

4

1 回答 1

3

你不需要这条线：

responseToClient.writeBytes(contentTypeLine);

您只需要调用HttpServletResponse#setHeader("Content-type, "application/json")设置适当的内容类型。

于 2013-06-06T20:57:39.490 回答