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使用 PHP 更新 SQL

屏幕消息是：

object(mysqli)[1]
  public 'affected_rows' => null
  public 'client_info' => null
  public 'client_version' => null
  public 'connect_errno' => null
  public 'connect_error' => null
  public 'errno' => null
  public 'error' => null
  public 'field_count' => null
  public 'host_info' => null
  public 'info' => null
  public 'insert_id' => null
  public 'server_info' => null
  public 'server_version' => null
  public 'stat' => null
  public 'sqlstate' => null
  public 'protocol_version' => null
  public 'thread_id' => null
  public 'warning_count' => null
No rows updated

我的代码是： 

$connection = @mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
if (mysqli_connect_error()) {
        die(`Connect Error: ` . mysqli_connect_error());
} else {
        echo `Successful connection to MySQL <br />`;

    $employ = $_POST['employer'];
    $address = $_POST['flat'];
    $login_name = $_POST['login_name'] ;
    var_dump($connection);

//    Insert employer and address into database row for logged in user.    

$query = "UPDATE members SET employer = `$employ`, flat = `$address` WHERE     login=`$login_name`";

if (!$result = $connection->query($query)) {
        echo "No rows updated <br />";
    } else {
            echo $result . " row(s) successfully updated<br />";
            }
    }



?>

我从中获取信息的表格是：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"

"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html>



<body>
<table width="100%" border="0" >
<tr>
<td colspan="2" style="background-color:#FFA500;">
</td>
</tr>

<td style="height:500px;width:400px; ">
<center>


<h2>Update</h2><br>


<form action="update.php" method="post">
<input type="hidden" name="login_name" value="$_SESSION['SESS_LOGIN']">

<p>employer <input type="text" name="employer"> </p>
<p>flat number <input type="text" name="flat"></p>
<p><input type="submit" value="Login" ></p>
</form>



</center>

</td>
</tr>

</table>

我一直试图让这个工作好几天。用户登录他们的个人资料，然后从 SQL 数据库中获取他们的所有信息，然后显示在屏幕上。上面的表格是使用特定信息更新他们的个人资料，以在他们下次登录时更新他们在数据库中的行。

4

1 回答 1

1

删除连接上的“@”以查看连接时出现的错误。正如您在连接对象中看到的那样，您没有数据库连接。

于 2013-06-06T17:09:18.973 回答