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我正在做一个简单的（ish）统计查询，我有几列是时间开始的，在查看项目时时间结束。我想要做的是返回您可以将某个项目的视图归类为反弹的次数。

目前查询能够返回所有必要的信息，到目前为止它相当简单，但这部分我遇到了一些麻烦。

这是我确定目前的错误方法。

IF(((UNIX_TIMESTAMP(v.time_ended) - UNIX_TIMESTAMP(v.time_started)) < 5), 1,0) bounce

我需要尝试获取每行的 UNIX_TIMESTAMP(v.time_ended) 并从 UNIX_TIMESTAMP(v.time_started) 中扣除它，看看这个值是否小于我归类为“反弹”的 5，如果是的话 + 1 到弹跳栏。

我只返回 1 行数据，但不确定如何执行，任何帮助将不胜感激。

谢谢

强尼

更新代码

SELECT i.id, 
i.title, 
i.slug, 
i.buyer_id as buyer_id, 
i.date_added as date_added, 
a.slug as area_slug, 
COUNT(o.id) as offers, 
COUNT(v.item_id) as total_item_views, 
(COUNT(v.item_id) / COUNT(o.id)) conversion,

SUM(CASE WHEN v.time_ended - v.time_started < 5 THEN 1 ELSE 0 END) 

FROM item as i
LEFT JOIN offer as o ON i.id=o.item_id
LEFT JOIN viewed_item as v ON i.id=v.item_id
INNER JOIN area as a ON a.id=i.area_id

WHERE i.id=3
4

1 回答 1

1

我想你想要这样的东西：

SELECT Item
      ,SUM(CASE WHEN v.time_ended - v.time_started < 5 THEN 1 ELSE 0 END))
FROM table
GROUP BY Item

从您更新的代码中，您完全缺少一个 group by：

SELECT i.id, i.title, i.slug, i.buyer_id as buyer_id, i.date_added as date_added, a.slug as area_slug, 
    COUNT(o.id) as offers, 
    COUNT(v.item_id) as total_item_views, 
    (COUNT(v.item_id) / COUNT(o.id)) conversion,
    SUM(CASE WHEN v.time_ended - v.time_started < 5 THEN 1 ELSE 0 END) 
FROM item as i
LEFT JOIN offer as o ON i.id=o.item_id
LEFT JOIN viewed_item as v ON i.id=v.item_id
INNER JOIN area as a ON a.id=i.area_id
WHERE i.id=3
GROUP BY  i.id, i.title, i.slug, i.buyer_id, i.date_added, a.slug
于 2013-06-06T16:35:53.450 回答