python - 检查是否没有列表元素包含搜索的子字符串

Question

我有清单：

myList = ['qwer', 'tyu', 'iop12', '3456789']

如何检查列表中的元素是否不包含搜索的子字符串，

• 对于字符串'wer'结果应为 False（包含子字符串的现有元素）
• 对于字符串'123'结果应该是 True （没有元素包含这样的子字符串）

Answer 1

not any(search in s for s in myList)

或者：

all(search not in s for s in myList)

例如：

>>> myList = ['qwer', 'tyu', 'iop12', '3456789']
>>> not any('wer' in s for s in myList)
False
>>> not any('123' in s for s in myList)
True

Answer 2

你可以使用any：

>>> myList = ['qwer', 'tyu', 'iop12', '3456789']
>>> not any('wer'  in x for x in myList)
False
>>> not any('123' in x for x in myList)
True

Answer 3

内置any和all函数非常有用。

not any(substring in element for element in myList)

测试运行表明

>>> myList = ['qwer', 'tyu', 'iop12', '3456789']
>>> substring = 'wer'
>>> not any(substring in element for element in myList)
False
>>> substring = '123'
>>> not any(substring in element for element in myList)
True