4

我正在尝试使用 jQuery AJAX 和通用处理程序上传图像文件。但似乎该文件没有被传递给处理程序。提交后context.Request.Files[0];始终为空:-/

我究竟做错了什么?

HTML:

<form id="form1" runat="server" method="post" enctype="multipart/form-data">

    <input name="file" id="file" type="file" />
    <input id="save" name="submit" value="Submit" type="submit" />

</form>

JS:

$().ready(function ()
{
    $('#file').change(function () 
    {
        sendFile(this.files[0]);
    });
});

function sendFile(file) 
{
    $.ajax({
        type: 'post',
        url: 'FileUpload.ashx',
        data: file,
        success: function () {
            // do something
        },
        xhrFields:
        {
            onprogress: function (progress) 
            {
                // calculate upload progress
                var percentage = Math.floor((progress.total / progress.totalSize) * 100);

                // log upload progress to console
                console.log('progress', percentage);

                if (percentage === 100) {
                    console.log('DONE!');
                }
            }
        },
        processData: false,
        contentType: 'multipart/form-data'
    });
}

阿什克斯:

public void ProcessRequest (HttpContext context) 
{
    HttpPostedFile file = context.Request.Files[0];

    if (file.ContentLength > 0)
    {
        //do something
    }
}
4

2 回答 2

8

设法让这个工作:)

这是我的代码...

///create a new FormData object
var formData = new FormData(); //var formData = new FormData($('form')[0]);

///get the file and append it to the FormData object
formData.append('file', $('#file')[0].files[0]);

///AJAX request
$.ajax(
{
    ///server script to process data
    url: "fileupload.ashx", //web service
    type: 'POST',
    complete: function ()
    {
        //on complete event     
    },
    progress: function (evt)
    {
        //progress event    
    },
    ///Ajax events
    beforeSend: function (e) {
        //before event  
    },
    success: function (e) {
        //success event
    },
    error: function (e) {
        //errorHandler
    },
    ///Form data
    data: formData,
    ///Options to tell JQuery not to process data or worry about content-type
    cache: false,
    contentType: false,
    processData: false
});
///end AJAX request
于 2014-02-12T18:50:41.557 回答
1

当我实现这样的事情时,我使用

var fd = new FormData();
fd.append(file.name,file);

并在 ajax 调用中,发送fd.

于 2013-06-06T13:56:58.233 回答