0

这是我的代码

for(id tempLangItem in jp.staffData)
        {
 NSMutableDictionary *temp=[[NSMutableDictionary alloc] initWithDictionary:tempLangItem];
            NSString *name = [temp objectForKey:@"lang_name"];
            NSLog(@"item_name =%@",name);
            NSLog(@"value in dictionary=%@",temp);



}  

这些是日志详细信息

item_name =marinieres

 value_in_dictionary={
    "lang_id" = 2;
    "lang_name" = "\U7a46\U840a\U65afmarinieres";
    time = "2013-06-05 05:14:50";
}

为什么它lang_name=\U7a46\U840a\U65afmarinieresvalue_in_dictionary日志中显示正确时给出item_name日志。

4

1 回答 1

2

试过了

NSMutableDictionary *temp=[[NSMutableDictionary alloc]init];
[temp setObject:@"marinieres" forKey:@"lang_name"];

NSString *name = [temp objectForKey:@"lang_name"];
NSLog(@"item_name =%@",name);
NSLog(@"value in dictionary=%@",temp);

以及我的日志显示的内容

2013-06-06 12:38:02.337 Cool[96423:11303] item_name =marinieres
2013-06-06 12:38:04.022 Cool[96423:11303] value in dictionary={
    "lang_name" = marinieres;
}

1 快速问题:如果它是一个 NSDictionary,你为什么要创建一个新实例?

 NSMutableDictionary *temp=[[NSMutableDictionary alloc] initWithDictionary:tempLangItem];

尝试tempLangItem

于 2013-06-06T07:09:34.563 回答