3

使用 http get request 我确实得到了这个 json 字符串：

hello
[
    {
        "upid":"1",
        "uptitle":"test",
        "uptype":"test",
        "upsize":"1234",
        "upname":"test",
        "upuid":"1",
        "uplocation":"1",
        "uptimestamp":"2013-04-11 09:25:40"
    },
    {
        "upid":"17",
        "uptitle":"test",
        "uptype":"video\/mov",
        "upsize":"2232",
        "upname":"testing",
        "upuid":"1",
        "uplocation":"",
        "uptimestamp":"2013-04-12 11:47:20"
    }
]

我怎样才能得到它的格式输出：

upid:1
uptitle:test
uptype:test
upsize:1234
upname:test
upuid:1
uplocation:1
uptimestamp:2013-04-11 09:25:40

upid:17
uptitle:test
uptype:video\/mov
upsize:2232
upname:testing
upuid:1
uplocation:
uptimestamp:2013-04-12 11:47:20

这是我的代码：

NSMutableURLRequest *GETrequest = [[NSMutableURLRequest alloc] init];
    [GETrequest setURL:[NSURL URLWithString:@"http:someip/upload/?id=1&command=alluseruploads&uid=1"]];
    [GETrequest setHTTPMethod:@"GET"];
    [GETrequest setValue:@"application/json;charset=UTF-8" forHTTPHeaderField:@"Content-Type"];

// And to send and receive an answer, use a NSURLResponse:
NSURLResponse *response;
NSData *GETReply = [NSURLConnection sendSynchronousRequest:GETrequest returningResponse:&response error:nil];
NSString *theReply = [[NSString alloc] initWithBytes:[GETReply bytes] length:[GETReply length] encoding: NSASCIIStringEncoding];
NSLog(@"Reply: %@", theReply);


// converting string to data
NSData *jsonData = [theReply dataUsingEncoding:NSUTF8StringEncoding];
//NSLog(@"dic = %@", jsonData);


NSError* error;

id jsonObject = [NSJSONSerialization JSONObjectWithData:jsonData options:0 error:&error];

NSLog(@"%@", jsonObject);
4

2 回答 2

11

您不必导入任何框架，因为它使用核心 iOS 框架。

如果你有一个NSString被叫jsonString，那么你可以做这样的事情......

NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];

// you can skip this step by just using the NSData that you get from the http request instead of converting it to a string.

id jsonObject = [NSJSONSerialization JSONObjectWithData:jsonData options: NSJSONReadingMutableContainers error:&localError];

NSLog(@"%@", jsonObject);

这将注销您的对象的控制台。它将是 anNSArray或 anNSDictionary并且将包含...的实例

NSDate
NSDictionary
NSArray
NSNumber
NSString

然后，您可以迭代此对象以获取数据。

好的，使用您的代码...

NSURLResponse *response;
NSData *getData = [NSURLConnection sendSynchronousRequest:getRequest returningResponse:&response error:nil];

NSError* error;

id jsonObject = [NSJSONSerialization JSONObjectWithData:getData options: NSJSONReadingMutableContainers error:&error];

NSLog(@"%@", jsonObject);
NSLog(@"%@", error);

这应该创建您的对象。您无需转换为字符串然后再转换回数据。

于 2013-06-05T12:39:35.713 回答
-1

使用 SBJson 库。它很容易。

于 2013-06-05T12:36:03.110 回答