0

我有一个具有这种结构的现有多维关联数组。它有3个元素。每个子数组有 3 个元素。

{"id":"723419","lat":33.217,"lon":-92.817,"dist":1437.15733534053},
{"id":"723424","lat":33.567,"lon":-91.717,"dist":1902.4556686060116},
{"id":"722447","lat":32.383,"lon":-94.717,"dist":2317.6870313059217},

我想用 3 个元素创建另一个（临时）数组，并循环遍历数组，向每个子数组添加一个元素，以便每个子数组有 4 个元素：

{"id":"723419","lat":33.217,"lon":-92.817,"dist":1437.15733534053,"elev":abc},
{"id":"723424","lat":33.567,"lon":-91.717,"dist":1902.4556686060116,"elev":def},
{"id":"722447","lat":32.383,"lon":-94.717,"dist":2317.6870313059217,"elev":ghi},

到目前为止，我已经尝试遍历我的临时数组

 for (var i in tempArray) { //loop through locations returned with elevation data
     multiArray[i]['elev']=...
 }

并将其视为一个对象（即使我将多数组声明为Array()

 for (var i in tempArray) { //loop through locations returned with elevation data
      multiArray.i.append(elev)=...
 }

两种方式，JS都抱怨multiArray[i]不存在。根据我对 JS 的了解，这应该可行。

谢谢您的帮助

4

1 回答 1

1

我做了一个简单的演示，它具有预定义的值，然后创建另一个数组，从第一个数组中获取它的值，然后添加新元素elev

var arr = [{
    "id": "723419",
        "lat": 33.217,
        "lon": -92.817,
        "dist": 1437.15733534053
}, {
    "id": "723424",
        "lat": 33.567,
        "lon": -91.717,
        "dist": 1902.4556686060116
}, {
    "id": "722447",
        "lat": 32.383,
        "lon": -94.717,
        "dist": 2317.6870313059217
}];
var tempArray = new Array();
for (var item in arr) {    
    tempArray.push(arr[item]);
    tempArray[item]["elev"] = "value"; //write here your value
}

JSFIDDLE

于 2013-06-05T10:49:46.390 回答