php - 使用 php 将文本从 html/javascript 中提取为字符串

Question

我有一个问题：我必须在 "body":{"text":" 和 ",单个变量的两个条件，由换行符分隔。我正在使用 PHP，已经在名为 $html 的变量中获得了整个 HTML。

这是代码：

[
   {
      "id":"537891442938686_1601777",
      "fbid":"537891612938669",
      "legacyid":"1601777",
      "body":{
         "text":"Jaaa:D",
         "ranges":[

         ],
         "aggregatedranges":[

         ]
      },
      "author":"1301211957",
      "ftentidentifier":"537891442938686",
      "likecount":0,
      "hasviewerliked":false,
      "canremove":false,
      "canreport":false,
      "canedit":false,
      "source":null,
      "istranslatable":false,
      "timestamp":{
         "time":1370411670,
         "text":"",
         "verbose":"4. junij 2013 ob 22:54"
      },
      "spamreplycount":0,
      "replyauthors":[

      ],
      "isfeatured":false
   },
   {
      "id":"537891442938686_1601790",
      "fbid":"537895309604966",
      "legacyid":"1601790",
      "body":{
         "text":"Takteri\u010d \u017ee sodelujem?? Hmm 5i\u010d?",
         "ranges":[

         ],
         "aggregatedranges":[

         ]
      },
      "author":"1087657810",
      "ftentidentifier":"537891442938686",
      "likecount":0,
      "hasviewerliked":false,
      "canremove":false,
      "canreport":false,
      "canedit":false,
      "source":null,
      "istranslatable":false,
      "timestamp":{
         "time":1370412832,
         "text":"",
         "verbose":"4. junij 2013 ob 23:13"
      },
      "spamreplycount":0,
      "replyauthors":[

      ],
      "isfeatured":false
   }
],
"profiles":[
   {
      "id":"1301211957",
      "name":"Maja Lamov\u0161ek",
      "firstName":"Maja",
      "vanity":"zmaychee",
      "thumbSrc":"https:\/\/fbcdn-profile-a.akamaihd.net\/hprofile-ak-ash4\/s32x32"
   }
]

多谢你们！！

Answer 1

您拥有的数据采用 JSON 格式。我强烈建议解码并将其放入对象中。之后，您可以轻松地遍历所需的所有属性。看看 json_decode ( http://php.net/manual/en/function.json-decode.php )。