shell - 使用 awk 或 sed 将十六进制转换为十进制

Question

我有这样的数据，用逗号分隔：

18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG1,2fe3,c7b1
18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG2,2fe3,c7b2
18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG3,2fe3,c7b3
03:25:55,Othercauses,N_Pancamukti,N_PancamuktiMG1,2f50,c775
03:25:55,Othercauses,N_Pancamukti,N_PancamuktiMG2,2f50,c776

我需要将最后两列转换为十进制，如下所示：

18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG1,12259,51121
18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG2,12259,51122
18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG3,12259,51123
03:25:55,Othercauses,N_Pancamukti,N_PancamuktiMG1,12112,51061
03:25:55,Othercauses,N_Pancamukti,N_PancamuktiMG2,12112,51062

我已经尝试过这个：
cat |nawk -F, '{printf "%d\n" , $1}'

我只得到零作为输出：
0 0 0 0 0 0 0 0 0

Answer 1

使用 Perl：

perl -lpe 's/([^,]*),([^,]*)$/hex($1).",".hex($2)/e' input

输出：

18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG1,12259,51121
18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG2,12259,51122
18:22:05,OtherOMoperation,BatuAmpar,BatuAmparMG3,12259,51123
03:25:55,Othercauses,N_Pancamukti,N_PancamuktiMG1,12112,51061
03:25:55,Othercauses,N_Pancamukti,N_PancamuktiMG2,12112,51062

和 gawk 中的类似：

gawk --non-decimal-data -F, '
      BEGIN{OFS=FS}{for(i=5;i<7;i++) $i=sprintf("%d","0x"$i)}1' input