假设画布不会很大或不会缩放到任意大小,我认为循环像素是有效的。
给定一个大的或任意大小的画布,我会创建一个画布的数组表示,并在你走的时候标记像素,记录用户至少点击了多少次。然后根据阈值测试该数字,该阈值确定必须刮掉多少票证才能将其视为“刮掉”。传入的伪代码
const int count = size_x * size_y; // pixel count
const int threshhold = 0.8 * count // user must hit 80% of the pixels to uncover
const int finger_radius = 2; // the radias of our finger in pixels
int scratched_pixels = 0;
bit [size_x][size_y] pixels_hit; // array of pixels all initialized to 0
void OnMouseDown(int pos_x, int pos_y)
{
// calculates the mouse position in the canvas
int canvas_pos_x, canvas_pos_y = MousePosToCanvasPos(pos_x, pos_y);
for(int x = canvas_pos_x - finger_rad; x < canvas_pos_x + brush_rad; ++x)
{
for(int y = canvas_pos_y - finger_rad; y < canvas_pos_y + brush_rad; ++y)
{
int dist_x = x - canvas_pos_x;
int dist_y = y - canvas_pos_y;
if((dist_x * dist_x + dist_y * dist_y) <= brush_rad * brush_rad
&& pixels_hit[x][y] == 0)
{
++scratched_pixels;
pixels_hit[x][y] = 1;
}
}
}
}
bool IsScratched()
{
if(scratched_pixels > threshhold)
return true;
else
return false;
}