34

Trying to get the raw data of the HTTP response content in requests in Python. I am interested in forwarding the response through another channel, which means that ideally the content should be as pristine as possible.

What would be a good way to do this?

4

3 回答 3

33

If you are using a requests.get call to obtain your HTTP response, you can use the raw attribute of the response. Here is the code from the requests docs.

>>> r = requests.get('https://github.com/timeline.json', stream=True)
>>> r.raw
<requests.packages.urllib3.response.HTTPResponse object at 0x101194810>
>>> r.raw.read(10)
'\x1f\x8b\x08\x00\x00\x00\x00\x00\x00\x03'
于 2013-06-04T17:45:44.017 回答
27

After requests.get(), you can use r.content to extract the raw Byte-type content.

r = requests.get('https://yourweb.com', stream=True)
r.content
于 2017-10-16T14:23:26.300 回答
2

To add to @brien answer, as stated in the docs:

In general, however, you should use a pattern like this to save what is being streamed to a file:

r = requests.get('https://yourweb.com', stream=True)

with open(filename, 'wb') as fd:
   for chunk in r.iter_content(chunk_size=128):
      fd.write(chunk)

Using Response.iter_content will handle a lot of what you would otherwise have to handle when using Response.raw directly. When streaming a download, the above is the preferred and recommended way to retrieve the content. Note that chunk_size can be freely adjusted to a number that may better fit your use cases.

That pattern not only has the advantages described above, but is also a good to fetch data in environments with limited memory.

于 2020-08-11T20:29:42.987 回答