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我有一个build.xml在命令行上运行良好的 Ant 文件：它编译、构建 JAR，并且我能够从 JAR 中执行 main 方法就好了。该build.xml文件引用了分散在各处的几个第三方库。构建 JAR 时，脚本不会将所有第三方库包含到 JAR 本身中。相反，它将它们的路径放入 JAR 的清单中。这有助于让我的 JAR 保持苗条和整洁。

我希望能够在 Eclipse 中编辑和调试我的项目，但我找不到一个简单的方法来做到这一点。我可以让我的项目使用 Ant 文件来构建项目，这似乎可行。但是，Eclipse 无法找到第三方库，因此 Eclipse 存在两个问题：

  1. 它显示（在文本编辑器中）很多编译错误，因为很多类是未定义的，并且
  2. 它无法执行 JAR。

我可以通过在两个不同的地方（即构建路径 viaProperties->Java Build Path->Libraries和执行类路径 via Run Configurations->Classpath）手动指定所有第三方库来解决上述两个问题。但似乎我不必手动执行此操作，因为所有第三方库都已列在我的 JAR 清单中。我究竟做错了什么？

这是我的build.xml文件：

<!-- Set global properties for this build -->
<property name="src"         location="./src" />
<property name="build"       location="./build"/>
<property name="dist"        location="./dist"/>
<property name="logs"        location="./logs"/>
<property name="docs"        location="./docs"/>
<property name="jar"         location="${dist}/dynamic_analyzer.jar"/>
<property name="lib"         location="../../thirdparty/lib"/>
<property name="hive-util"   location="../../hive-utils/dist"/>
<property name="hpdb"        location="../../hive-db/hpdb/dist"/>
<property name="static"      location="../../hive-backend/static_analyzer/dist"/>
<property name="mainclass"   value="com.datawarellc.main.DynamicMain"/>

<path id="dep.runtime">
    <fileset dir="${lib}"       includes="**/*.jar"/>
    <fileset dir="${hive-util}" includes="**/*.jar"/>
    <fileset dir="${hpdb}"      includes="**/*.jar"/>
    <fileset dir="${static}"    includes="**/*.jar"/>
</path>

<target name="clean">
    <delete dir="${build}"/>
    <delete dir="${dist}"/>
    <delete dir="${docs}"/>
    <delete dir="${logs}"/>
</target>

<target name="init">
    <tstamp/>
    <mkdir dir="${build}"/>
    <mkdir dir="${dist}"/>
    <mkdir dir="${logs}"/>
</target>

<target name="compile" depends="init">
    <javac srcdir="${src}" destdir="${build}" debug="on" includeantruntime="false">
        <classpath refid="dep.runtime" />
    </javac>

    <!-- Debug output of classpath -->
    <property name="myclasspath" refid="dep.runtime"/>
    <echo message="Classpath = ${myclasspath}"/>

</target>

<target name="jar" depends="compile">
    <!-- Put the classpath in the manifest -->
    <manifestclasspath property="manifest_cp" jarfile="${jar}" maxParentLevels="10">
        <classpath refid="dep.runtime" />
    </manifestclasspath>

    <jar jarfile="${jar}" basedir="${build}">
        <manifest>
            <attribute name="Main-Class" value="${mainclass}"/>
            <attribute name="Class-Path" value="${manifest_cp}"/>
        </manifest>
        <zipfileset dir="${src}" includes="**/*.xml" />
    </jar>
</target>

${lib}您可以看到我在几个目录（ 、${hive-util}、${hpdb}和${static}）中有第三方库。我使用这些来创建一个path名为dep.runtime. 然后我在构建我的 jar 时包含dep.runtime在清单中。如何让 Eclipsedep.runtime在执行时对构建路径和类路径使用相同的内容？

4

2 回答 2

3

perl 的替代方法是使用嵌入式groovy 任务：

<project name="demo" default="eclipse-files">

    <property name="src.dir"     location="src"/>
    <property name="classes.dir" location="build/classes"/>

    <path id="dep.runtime">
       <fileset dir="${lib}"       includes="**/*.jar"/>
       <fileset dir="${hive-util}" includes="**/*.jar"/>
       <fileset dir="${hpdb}"      includes="**/*.jar"/>
       <fileset dir="${static}"    includes="**/*.jar"/>
    </path>

    <target name="bootstrap">
        <mkdir dir="${user.home}/.ant/lib"/>
        <get dest="${user.home}/.ant/lib/groovy-all.jar" src="http://search.maven.org/remotecontent?filepath=org/codehaus/groovy/groovy-all/2.1.4/groovy-all-2.1.4.jar"/>
    </target>

    <target name="eclipse-files">
        <taskdef name="groovy" classname="org.codehaus.groovy.ant.Groovy"/>
        <groovy>
            import groovy.xml.MarkupBuilder

            project.log "Creating .classpath"

            new File(".classpath").withWriter { writer ->
                def xml = new MarkupBuilder(writer)

                xml.classpath() {
                    classpathentry(kind:"src",    path:properties["src.dir"])
                    classpathentry(kind:"output", path:properties["classes.dir"])
                    classpathentry(kind:"con",    path:"org.eclipse.jdt.launching.JRE_CONTAINER")

                    project.references."dep.runtime".each {
                        classpathentry(kind:"lib", path:it)
                    }
                }
            }
        </groovy>
    </target>

    <target name="clean">
        <delete file=".classpath"/>
    </target>

</project>

笔记：

  • 引导目标将下载第 3 方 groovy jar（不依赖 perl）
  • Groovy 可以直接访问“dep.runtime”ANT 路径并遍历其内容
  • Groovy 对编写 XML 文件有很好的支持。

以下答案类似，并且另外生成 Eclipse .project 文件。

于 2013-06-04T20:44:57.700 回答
2

I came up with the following workaround, inspired by the link provided by @leeand00.

First, I wrote a simple Perl script (called genClasspath.pl) that generates the .classpath file that Eclipse uses. 

#!/usr/bin/perl
use strict;

if (@ARGV != 2) {
  print STDERR "Usage: $0 OUTFILE CLASSPATHSTRING\n";
  print STDERR "e.g., $0 .classpath path1:path2:path3\n";
  exit 1;
}

my $OUTFILE         = $ARGV[0];
my $CLASSPATHSTRING = $ARGV[1];

open my $out_fh, '>', $OUTFILE or die "Couldn't open output file: $!";

print $out_fh q{<?xml version="1.0" encoding="UTF-8"?>
<classpath>
    <classpathentry kind="src" path="src"/>
    <classpathentry kind="con" path="org.eclipse.jdt.launching.JRE_CONTAINER"/>
    <classpathentry kind="output" path="build"/>
};

my @libs = split(":", $CLASSPATHSTRING);
foreach my $thisLib (@libs){
    print $out_fh "    <classpathentry kind=\"lib\" path=\"$thisLib\"/>\n";
}
print $out_fh "</classpath>\n";

Then, I have my build.xml file call this script with the content of dep.runtime:

<target name="compile" depends="init">
    <javac srcdir="${src}" destdir="${build}" debug="on" includeantruntime="false">
        <classpath refid="dep.runtime" />
    </javac>

    <property name="myclasspath" refid="dep.runtime"/>

    <exec dir="." executable="../../scripts/genClasspath.pl" os="Linux">
        <arg value=".classpath"/>
        <arg value="${myclasspath}"/>
    </exec>

</target>

The only catch is that I need to run Ant on the command line at least once before I open the project in Eclipse. But when I do, Eclipse is able to compile and execute my project just fine, since the classpath is exactly the same as Ant's.

于 2013-06-04T13:22:59.917 回答