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我想在网站上自动显示每个月的第一个和第三个星期一。如果当前日期在第一个星期一之后，则只需显示第三个星期一。

我修改了在论坛上找到的代码并进行了一些更改，但由于 php 知识有限，我无法验证它是否会提供正确的结果。

$time = strtotime("first Monday of ".$monthname." ".$year); 
$time2 = strtotime("third Monday of ".$monthname." ".$year); 
{
    if ($time2 > $time) {
        echo date('d-m-Y',$time2)." ".$monthname;
    }
    else {
        echo date('d-m-Y',$time)." ".$monthname;
    }
}
4

1 回答 1

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我不完全确定你的意思，但这应该做我认为你想要的：

$time1 = strtotime("first Monday of {$monthname} {$year}"); 
$time2 = strtotime("third Monday of {$monthname} {$year}");
echo date('jS F Y', time() > $time1 ? $time2 : $time1); // e.g. 1st January 1970

Thetime() > $time1 ? $time2 : $time1是一个三元条件，基本上意味着

condition ? if_true : if_false

按照您编写的方式，我认为您需要知道可以将变量放在双引号内，例如

$a = 'first';
echo "The $a day of the week"; // echoes 'The first day of the week

但不是单引号，例如

$a = 'first';
echo 'The $a day of the week'; // echoes 'The $a day of the week.

我在变量周围加上了大括号，这样我就可以做到

$a = 'first';
$b = 'variable';
echo "This is the {$a}_{$b}"; // Echoes 'This is the first_variable'

没有大括号

echo "This is the $a_$b" // Undefined variable $a_

或者

try {
    // Do something
} catch (Exception $ex) {
    echo "There was an error and the message was {$ex->getMessage()}";
}
于 2014-02-27T15:29:31.567 回答