我正在尝试更新数据库中的记录,我正在使用以下代码来执行此操作,
System.out.print("Update");
Session session1 = HibernateUtil.getSessionFactory().openSession();
Query q = session1.createQuery("FROM Developer WHERE id = :id");
q.setParameter("id", 1);
Developer developer = (Developer)q.list().get(0);
developer.setContact("Jack");
session1.update(developer);
一旦我运行该项目,它会在控制台上显示以下内容并且不会进一步。
INFO: Update
INFO: Hibernate: select developer0_.id as id0_, developer0_.contact as contact0_,
developer0_.phone_1 as phone3_0_
from developer developer0_ where developer0_.id=?
开发者.java
package net.viralpatel.contact.model;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
/**
*
* @author Jack
*/
@Entity
@Table(name="developer")
public class Developer implements Serializable {
private static final long serialVersionUID = -8767337896773261247L;
private int id;
private String contact;
private int phone_1;
@Id
@GeneratedValue
@Column(name="id")
public int getID() {
return id;
}
public void setID(int ID) {
this.id = ID;
}
@Column(name="contact")
public String getContact() {
return contact;
}
public void setContact(String Contact) {
this.contact = Contact;
}
@Column(name="phone_1")
public int getPhone_1() {
return phone_1;
}
public void setPhone_1(int Phone_1) {
this.phone_1 = Phone_1;
}
}
我可以使用以下代码将行插入数据库的同一个表中
Session session1 = HibernateUtil.getSessionFactory().openSession();
session1.beginTransaction();
session1.save(developer);
session1.getTransaction().commit();