我正在从网站获取数据，并且在 android 中显示为 listview，但是它显示了一些 html 标签，其中还包括我的 listview 中的数据。
应用适配器.java
public class ApplicationAdapter extends ArrayAdapter<Application>
{
private List<Application> items;
private LayoutInflater inflator;
public ApplicationAdapter(Context context, List<Application> items)
{
super(context, R.layout.activity_row, items);
this.items = items;
inflator = LayoutInflater.from(getContext());
}
@Override
public int getCount()
{
return items.size();
}
@Override
public View getView(int position, View convertView, ViewGroup parent)
{
ViewHolder holder = null;
//View v = convertView;
if ( convertView == null )
{
convertView = inflator.inflate(R.layout.activity_row, null);
LayoutInflater li = LayoutInflater.from(getContext());
//convertView = inflator.inflate(R.layout.app_custom_list, null);
holder = new ViewHolder();
holder.text1 = (TextView) convertView.findViewById(R.id.text1);
holder.chk = (CheckBox) convertView.findViewById(R.id.checkbox);
/*holder.chk
.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
/*@Override
public void onCheckedChanged(CompoundButton view,
boolean isChecked) {
int getPosition = (Integer) view.getTag();
items.get(getPosition).setSelected(view.isChecked());
}
});*/
convertView.setTag(holder);
convertView.setTag(R.id.text1, holder.text1);
convertView.setTag(R.id.checkbox, holder.chk);
}else {
holder = (ViewHolder) convertView.getTag();
}
Application app = items.get(position);
holder.chk.setTag(position);
holder.text1.setText(items.get(position).getContent());
//holder.chk.setChecked(items.get(position).isSelected());
if ( app != null )
{
TextView titleText = (TextView) convertView.findViewById(R.id.titleTxt);
if ( titleText != null )
titleText.setText(Html.fromHtml(app.getContent()).toString());
//titleText.setText(app.getContent());
//holder.chk.setChecked(((View) Html.fromHtml(app.getContent())).isSelected());
}
return convertView;
}
static class ViewHolder {
public TextView text1;
public CheckBox chk;
}
//return convertView;
}
尽管我使用了一行来删除 listview 中的 html 标签，但我不知道它是否像
我的 listview 一样显示 html 标签。我的输出在 listview 中显示类似 hi <br>bye <br>' hello 。<br>但我不想在我的 listview 中显示 html 标签，我该如何解决这个问题。
Mainactivity.java
public class MainActivity extends Activity implements FetchDataListener
{
private static final int ACTIVITY_CREATE=0;
private ProgressDialog dialog;
ListView lv;
//private ProjectsDbAdapter mDbHelper;
//private SimpleCursorAdapter dataAdapter;
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_list_item);
//mDbHelper = new ProjectsDbAdapter(this);
//mDbHelper.open();
//fillData();
//registerForContextMenu(getListView());
lv =(ListView)findViewById(R.id.list);
initView();
}
private void initView()
{
// show progress dialog
dialog = ProgressDialog.show(this, "", "Loading...");
String url = "http://dry-brushlands-3645.herokuapp.com/posts.json";
FetchDataTask task = new FetchDataTask(this);
task.execute(url);
//mDbHelper.open();
//Cursor projectsCursor = mDbHelper.fetchAllProjects();
//startManagingCursor(projectsCursor);
// Create an array to specify the fields we want to display in the list (only TITLE)
//String[] from = new String[]{ProjectsDbAdapter.KEY_TITLE};
// and an array of the fields we want to bind those fields to (in this case just text1)
//int[] to = new int[]{R.id.text1};
/* Now create a simple cursor adapter and set it to display
SimpleCursorAdapter projects =
new SimpleCursorAdapter(this, R.layout.activity_row, projectsCursor, from, to);
setListAdapter(projects);
*/
// create the adapter using the cursor pointing to the desired data
//as well as the layout information
/*dataAdapter = new SimpleCursorAdapter(
this, R.layout.activity_row,
projectsCursor,
from,
to,
0);
setListAdapter(dataAdapter);
*/
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
//getMenuInflater().inflate(R.menu.activity_main, menu);
super.onCreateOptionsMenu(menu);
MenuInflater mi = getMenuInflater();
mi.inflate(R.menu.activity_main, menu);
return true;
}
@Override
public boolean onMenuItemSelected(int featureId, MenuItem item) {
createProject();
return super.onMenuItemSelected(featureId, item);
}
private void createProject() {
Intent i = new Intent(this, ProjectEditActivity.class);
startActivityForResult(i, ACTIVITY_CREATE);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent intent) {
super.onActivityResult(requestCode, resultCode, intent);
initView();
}
@Override
public void onFetchComplete(List<Application> data)
{
// dismiss the progress dialog
if ( dialog != null )
dialog.dismiss();
// create new adapter
ApplicationAdapter adapter = new ApplicationAdapter(this, data);
// set the adapter to list
lv.setAdapter(adapter);
}
@Override
public void onFetchFailure(String msg)
{
// dismiss the progress dialog
if ( dialog != null )
dialog.dismiss();
// show failure message
Toast.makeText(this, msg, Toast.LENGTH_LONG).show();
}
}
我只想显示列表视图数据，不需要 htmltags
我想知道如果（titleText！= null）那么哪一行是正确的，
titleText.setText(Html.fromHtml(app.getContent()).toString());或者我想这样写holder.text1.setText(Html.fromHtml(app.getContent()).toString());