0

嗨，我打印时的功能输出是 

average = ['2.06556473829 is the average for a', 
           '1.48154269972 is the average for b', 
           '1.56749311295 is the average for c',
           '2.29421487603 is the average for d', 
           '1.51074380165 is the average for e', 
           '1.46997245179 is the average for f', 
           '1.15950413223 is the average for g', 
           '1.94159779614 is the average for h', 
           '1.48236914601 is the rainfall average for i',
           '1.2914600551 is the average for j']

我想要做的是只取列表中的所有整数，即 2.06555、1.222 等。将它们全部相加，然后将总和除以列表中的项目数并打印结果

目前我有一个总变量

total= sum(int(average))/len(average)
print total

然而，我的代码似乎不允许我挑选出所有的整数并将它们相加。无论如何我只能选择整数来求和然后得到平均值吗？

谢谢你的帮助。

4

1 回答 1

2 
>>> average = ['2.06556473829 is the average for a', '1.48154269972 is the average for b', '1.56749311295 is the average for c', '2.29421487603 is the average for d', '1.51074380165 is the average for e', '1.46997245179 is the average for f', '1.15950413223 is the average for g', '1.94159779614 is the average for h', '1.48236914601 is the rainfall average for i', '1.2914600551 is the average for j']
>>> avgs = [float(x.split()[0]) for x in average]
>>> sum(avgs)/len(avgs)
1.626446280991

要获取int列表中数字的平均值：

>>> avgs = [ int(float(x.split()[0])) for x in average]
>>> sum(avgs)/float(len(avgs))
1.2

你也可以regex用来获取整数：

>>> import re
>>> [ int(re.search(r'\d+',x).group(0)) for x in average]
[2, 1, 1, 2, 1, 1, 1, 1, 1, 1]
于 2013-06-04T02:35:17.043 回答