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我有一个从称为站的数据创建的列表 = []

打印为

 ['france', 'england', 'germany', 'china', 'paris', 'sydney', 'gold coast', 'canberra', 'perth', 'melbourne']

我还有另一个功能 x 打印时打印。

[0.0, 3043.004178666758, 21558.2996208357, 40246.748450913066, 40908.82213277263, 43786.0579097594, 67781.1426515405, 79693.11338661514, 65046.35819797423, 92804.01912347642]

我有两个问题。

首先）有没有办法将两者结合起来，即我可以打印一个新的列表或打印的函数

[france = 0.0, england = 3043.004, germany = 21558.2999] and so on

其次，我可以创建变量或列表或诸如法国保持值 = 0.0 的东西，这样如果稍后产生 0.0，我可以调用法国和法国变量中的任何数据吗？

4

1 回答 1

5

dict与 一起使用zip：

>>> lis1 = ['france', 'england', 'germany', 'china', 'paris', 'sydney', 'gold coast', 'canberra', 'perth', 'melbourne']
>>> lis2 = [0.0, 3043.004178666758, 21558.2996208357, 40246.748450913066, 40908.82213277263, 43786.0579097594, 67781.1426515405, 79693.11338661514, 65046.35819797423, 92804.01912347642]
>>> dic = dict(zip(lis1,lis2))
>>> dic 
{'canberra': 79693.11338661514,
 'china': 40246.748450913066,
 'england': 3043.004178666758,
 'france': 0.0,
 'germany': 21558.2996208357,
 'gold coast': 67781.1426515405,
 'melbourne': 92804.01912347642,
 'paris': 40908.82213277263,
 'perth': 65046.35819797423,
 'sydney': 43786.0579097594}

# Fetching values
>>> dic['france']
0.0
>>> dic['sydney']
43786.0579097594

打印键和值：

>>> for k,v in dic.iteritems():
        # k points to the key, and v points to the value
        if v < distance:
            print k,"is less than", distance
        else:    
            print k,"is greater than or equal to",distance
...         
england is greater than or equal to 1000
canberra is greater than or equal to 1000
paris is greater than or equal to 1000
france is less than 1000
melbourne is greater than or equal to 1000
germany is greater than or equal to 1000
sydney is greater than or equal to 1000
china is greater than or equal to 1000
gold coast is greater than or equal to 1000
perth is greater than or equal to 1000
于 2013-06-03T23:30:40.300 回答