23

我需要将完整的 xml 文档存储为 json 对象的一部分。当我收到请求并尝试从 json 字符串创建 json 对象时,如下所示 -

{"content":{
"name" : "xyz",
"details":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>
 <ns0:Report xmlns:ns0=\"http://www.khisko.com/triTypes\">
  <StackTrace>Job-8004 Error in [xxxxxxxxxx]
      Output data invalid&#xD;
  at com.xyz.tst.a(Unknown Source)&#xD;
      caused by: java.lang.NullPointerException&#xD;
   </StackTrace>
   <Msg>Output data invalid</Msg>
  </ns0:Report>"
 }}

我在详细信息的第一个字符处收到未终止的字符串错误。我该如何处理。

我正在使用 org.json.JSONObject 构造函数,该构造函数将 java 字符串作为参数并将上面的 json 作为 java 字符串传递。

谢谢

4

3 回答 3

25

您可以对 xml 字符串进行编码和解码,例如

{
  "content": {
    "name": "xyz",
    "details": "PD94bWwgdmVyc2lvbj1cIjEuMFwiIGVuY29kaW5nPVwiVVRGLThcIj8+CiA8bnMwOlJlcG9ydCB4bWxuczpuczA9XCJodHRwOi8vd3d3LmtoaXNrby5jb20vdHJpVHlwZXNcIj4KICA8U3RhY2tUcmFjZT5Kb2ItODAwNCBFcnJvciBpbiBbeHh4eHh4eHh4eF0KICAgICAgT3V0cHV0IGRhdGEgaW52YWxpZCYjeEQ7CiAgYXQgY29tLnh5ei50c3QuYShVbmtub3duIFNvdXJjZSkmI3hEOwogICAgICBjYXVzZWQgYnk6IGphdmEubGFuZy5OdWxsUG9pbnRlckV4Y2VwdGlvbiYjeEQ7CiAgIDwvU3RhY2tUcmFjZT4KICAgPE1zZz5PdXRwdXQgZGF0YSBpbnZhbGlkPC9Nc2c+CiAgPC9uczA6UmVwb3J0Pg==",
    "encoding": "base64"
  }
}
于 2019-01-21T10:27:58.493 回答
13

只是我已经改成\"@Explosion 'Pillsremove line breaks

{"content":{
    "name" : "xyz",
    "details":"<?xml version='1.0' encoding='UTF-8'?>
     <ns0:Report xmlns:ns0='http://www.khisko.com/triTypes'>
      <StackTrace>Job-8004 Error in [xxxxxxxxxx]
          Output data invalid&#xD;
      at com.xyz.tst.a(Unknown Source)&#xD;
          caused by: java.lang.NullPointerException&#xD;
       </StackTrace>
       <Msg>Output data invalid</Msg>
      </ns0:Report>"
     }}
于 2015-12-21T21:24:09.693 回答
4

Don't want to remove the line breaks from the xml but made change in json java class to not throw unterminated string exception for NL, CR. thanks Explosion Pills.

于 2013-06-06T15:24:46.347 回答