1

我有一个存储过程，我将它连接到我的项目，我想知道如何传递不同的参数类型：

存储过程：

  [dbo].[UploadAssignment]  
          @studentId int    
    , @guid uniqueidentifier  
    , @originalfilename nvarchar(500)   
    , @uploaddate datetime

在我的项目中：

public virtual IEnumerable<T> GetUploadStudentSubmission<T>(int studentId, .."How should i format the remaining parameters")  
{  
   SqlCommand _command = new SqlCommand("dbo.UploadAssignment");  
   _command.CommandType = CommandType.StoredProcedure;  
   _command.Parameters.Add(new SqlParameter { ParameterName = "studentId",SqlDbType = SqlDbType.Int, Value = sectionId});  
   _command.Parameters.Add(new SqlParameter { ParameterName = "guid", SqlDbType = SqlDbType.Int, Value = guid });  
   _command.Parameters.Add(new SqlParameter { ParameterName = "originalfilename", SqlDbType = SqlDbType.Int, Value = originalfilename });  
   _command.Parameters.Add(new SqlParameter { ParameterName = "uploaddate", SqlDbType = SqlDbType.Int, Value = uploaddate });
}
4

4 回答 4

2

官方文档指出：

ParameterName 以 形式指定@paramname。

因此，您需要@在参数名称中包含 。除此之外，您只需要像传递给任何其他函数一样传递相关参数，如下所示：

public virtual IEnumerable<T> GetUploadStudentSubmission<T>(
    int studentId, Guid guid, string originalfilename, DateTime uploaddate)
{  
    SqlCommand _command = new SqlCommand("dbo.UploadAssignment");  
    _command.CommandType = CommandType.StoredProcedure;  
    _command.Parameters.Add(new SqlParameter { ParameterName = "@studentId",SqlDbType = SqlDbType.Int, Value = sectionId});  
    _command.Parameters.Add(new SqlParameter { ParameterName = "@guid", SqlDbType = SqlDbType.UniqueIdentifier, Value = guid });  
    _command.Parameters.Add(new SqlParameter { ParameterName = "@originalfilename", SqlDbType = SqlDbType.NVarChar, Value = originalfilename });  
    _command.Parameters.Add(new SqlParameter { ParameterName = "@uploaddate", SqlDbType = SqlDbType.DateTime, Value = uploaddate });
}
于 2013-06-03T19:59:52.663 回答
1 
public virtual IEnumerable<T> GetUploadStudentSubmission<T>(int studentId, Guid guid, string originalfilename, DateTime uploaddate)  
{  
    SqlCommand _command = new SqlCommand("dbo.UploadAssignment");  
    _command.CommandType = CommandType.StoredProcedure;  
    _command.Parameters.AddWithValue("@studentId",sectionId);  
    _command.Parameters.AddWithValue("@guid", guid );  
    _command.Parameters.AddWithValue("@originalfilename",  originalfilename);  
    _command.Parameters.AddWithValue("@uploaddate", uploaddate);
}
于 2013-06-03T20:11:27.887 回答
0

您还可以使用以下代码：

public virtual IEnumerable<T> GetUploadStudentSubmission<T>(int studentId, Guid guid,    string originalfilename, DateTime uploaddate)  
{ 
    var command = Database.GetStoredProcCommand("[dbo].[UploadAssignment]");
    Database.AddInParameter(command, "studentId", DbType.Int32, studentId);
    Database.AddInParameter(command, "guid", DbType.Guid, guid);
    Database.AddInParameter(command, "originalfilename", DbType.String, originalfilename);
    Database.AddInParameter(command, "uploaddate", DbType.DateTime, uploaddate);

    var reader = Database.ExecuteReader(command);
    commandText = command.CommandAsSql();
    reader.Close();
}
于 2013-06-03T20:16:46.990 回答
0

Microsoft 还提供了出色的企业库，除其他内容外，它还包含一个 DataAccess 块并处理参数。

有关更多详细信息，请参阅此答案https://stackoverflow.com/a/3038469/69433

于 2013-06-03T20:23:11.423 回答