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如何将“Joe Smith”映射到名字“Joe”姓氏“Smith”?

我已经有了拆分名称的代码,但我不确定如何使用 Digester 进行操作。

<guestlist>
  <guest>
   <name>Joe Smith</name>
  </guest>
</guestlist>

public class Guest(){
  private String firstName;
  private String lastName;
...
}
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2 回答 2

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一个简单的答案是:向您的 Guest 类添加一个附加属性:

public class Guest {
    private String firstName;
    private String lastName;
    public void setBothNames(String bothNames) {
        String[] split = bothNames.split(" ");
        firstName = split[0];
        lastName = split[1];
    }

以及消化器的 bean 属性设置器规则:

    digester.addBeanPropertySetter("guestlist/guest/name", "bothNames");
于 2009-11-06T21:31:30.750 回答
0
// Loading from a file, you can also load from a stream
XDocument loaded = XDocument.Load(@"C:\Guests.xml");


// Query the data and write out a subset of guests

var guests= from c in loaded.Descendants("guest")
        select new
        {
            FirstName = SplitFunc_FirstName(c.Element("name")),
            LastName = SplitFunc_LastName(c.Element("name"))
        };

foreach (var guest in guests)
{
    Your custom code...to attach it to your entity object.
}

注意:SplitFunc_FirstName 是您已经编写的用于提取名字和姓氏的自定义函数。

于 2009-11-06T20:51:09.633 回答