sql - 选择 1 条记录，其中两条记录在不同列中具有相同的值

Question

我有一个包含两列的表。

在前两行中，列的值是相反的，我如何为每个实例选择一个记录，其中一个 STATION_1_I 等于另一个记录 STATION_2_I 并且它的 STATION_2_I 等于 STATION_1_I。

Answer 1

INTERSECT将为您删除重复项

select "station_1_I", "station_2_I" from mytable
intersect
select "station_2_I", "station_1_I" from mytable 
             where "station_2_I" < "station_1_I"

SQL小提琴

Answer 2

select a,b from
(
select 
(case when a<b then a else b end) as a,
(case when a>b then a else b end) as b
from (
select station_1_I as a, station_2_I as b from MyTable
union all
select station_2_I, station_1_I from MyTable
) having count(*)=2 group by a,b
) group by a,b