mysql - mysql不同的选择查询合二为一

Question

我如何通过一个查询获得以下信息：我想从我的评论表中获得所有对给定 post_id 进行评论的人，然后根据用户的姓名检查用户评论了多少次。我想避免对它进行 2 个不同的查询

我一直在尝试以下但不会返回预期结果

SELECT comments.*, COUNT(approved.comment_approved) AS has_commented  FROM wp_comments AS comments  
    INNER JOIN wp_comments AS approved 
    ON comments.comment_author = approved.comment_author

WHERE comments.comment_post_ID =14616
GROUP BY comments.comment_content

Answer 1

你不应该分组post_ID吗？（那只会返回一行）

SELECT
  comments.*
, COUNT(approved.comment_approved) AS "has_commented"
FROM wp_comments AS comments
JOIN wp_comments AS approved
  ON (comments.comment_author = approved.comment_author)
WHERE comments.comment_post_ID = 14616
GROUP BY comments.comment_post_ID
;

还是您希望每个“已批准”评论一行？