0

我的数据库中有这个日期11/06/2013 12:00

这是我的代码和我想要的格式

$dateformatstart = date_format(date_create($row['datestart']), 'D j M y H:i');

虽然它作为

Wed 6 Nov 13 12:00

以为月是日,日是月,不知道为什么

谢谢

4

2 回答 2

2

在问这个问题之前,你甚至检查过php 手册吗?

好吧,这里有一些关于如何在 PHP 中格式化日期的巧妙方法

<?php
// Assuming today is March 10th, 2001, 5:16:18 pm, and that we are in the
// Mountain Standard Time (MST) Time Zone

$today = date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today = date("m.d.y");                         // 03.10.01
$today = date("j, n, Y");                       // 10, 3, 2001
$today = date("Ymd");                           // 20010310
$today = date('h-i-s, j-m-y, it is w Day');     // 05-16-18, 10-03-01, 1631 1618 6 Satpm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.');   // it is the 10th day.
$today = date("D M j G:i:s T Y");               // Sat Mar 10 17:16:18 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:18 m is month
$today = date("H:i:s");                         // 17:16:18
$today = date("Y/m/d H:i");                   // 2001-03-10 17:16:18 (the MySQL DATETIME format)

如果您尝试输出这样的数据格式:

11/06/2013 12:00

那么更好,使用

$today = date("d/m/Y H:i");

于 2013-06-03T00:15:47.203 回答
2

也许这有帮助:

$date = DateTime::createFromFormat('d/m/Y H:i', $row['datestart']);

$dateformatstart = date_format($date, 'D j M y H:i');
于 2013-06-03T00:24:02.640 回答