mysql - 查询：其中隐藏 = '0'

Question

如何使我的搜索表单仅列出hidden = '0';+ 其余选项的结果？

$stmt = $dbh->prepare("
SELECT *
FROM        users u
LEFT JOIN   menues m
ON          u.user_id = m.restaurant_id
WHERE       (restaurant LIKE CONCAT('%', :term, '%'))
OR          city LIKE CONCAT('%', :term, '%')
");
$stmt->bindParam(":term", $term);
$stmt->execute();   

提前致谢 ：）

Answer 1

你可以不只是添加

AND hidden = '0'

到您的WHERE子句末尾，以便您的查询结束

.
.
.
WHERE (restaurant LIKE ...
OR city LIKE ...)
AND hidden='0'

顺便说一句hidden真的是基于字符的列吗？如果没有，您应该添加hidden=0（不带单引号）

Answer 2

好吧，我希望我了解您的需求：

$stmt = $dbh->prepare("
SELECT *
FROM        users u
LEFT JOIN   menues m
ON          u.user_id = m.restaurant_id
WHERE       (((restaurant LIKE CONCAT('%', :term, '%'))
OR          city LIKE CONCAT('%', :term, '%'))
AND         hidden = 0)
");
$stmt->bindParam(":term", $term);
$stmt->execute();