mysql - 与某个值最接近的两个值

Question

我有一张表，上面有点X和Y。我需要找到最接近原点的Xand点。Y(0, 0)

我正在尝试这种方式：

SELECT *
FROM `line` 
WHERE xi < yi and 0 < xi and 0 < yi and yi < xi
ORDER BY yi and xi  ASC 
Limit 100

但我没有得到想要的值。

Answer 1

到原点的距离由 给出sqrt(xi^2 +yi^2)。由于平方根是严格升序的，您可以省略它以进行排序。这给出了：

SELECT *
FROM `line` 
ORDER BY xi*xi + yi*yi
Limit 100

Answer 2

您需要计算距离d = sqrt(x²+y²)以获取距原点最近的点

select x, y, sqrt(x*x + y*y) as distance
from `line` 
order by distance asc
limit 1

Answer 3

SELECT xi, yi, xi * xi + yi * yi As r2
FROM line
ORDER BY r2