5

因此,我使用 php 构建了一个向导,其中一个表单要求用户上传图像。

我已经构建了所有内容,唯一的问题是我必须能够在我的一个 if 语句中说,如果表单是使用 jquery 的 submit() 方法提交的。

所以这里是用户选择图像后在 jquery 中提交表单的代码。

var initUpload = function(){
    $('.filebutton').change(function(e){
        $("form").submit();
    });
};

这就是我的 if 语句的外观。

if($this->input->post('back')){

   //Tells me that the user clicked on the back button, and to go back 1 step in the wizard.    

}else if(???){

   //This is where I would like to say: if form was submitted with jquery.      

}else{

   //Else the user just clicked "next" and to continue normally.

}

我已经知道的:

使用$this->input->post('back')我可以检查表单是否使用带有valueBACK 的按钮提交。我有var_dumped $this->input->post(),但它只返回输入字段的值。

4

1 回答 1

4

如上面的评论,我被要求发表我的评论作为答案,所以你去

if($this->input->post('back')){

//Tells me that the user clicked on the back button, and to go back 1 step in the wizard.    

}else if($_FILES['your_image_filed_name']){

//This is where I would like to say: if form was submitted with jquery.  
//you can use codeigniter's built in Upload libraray which v easy      

}else{

 //Else the user just clicked "next" and to continue normally.

 }

这是upload代码看看

   $config_logo_image = array(
    'allowed_types' => 'jpg|jpeg|gif|png',
    'upload_path' => UPLOAD_PATH,//root path for image
    'max_size' => 2000,
    );
$this->load->library('upload', $config_logo_image );                    
if($this->upload->do_upload('your_image_filed_name')){

$logo_image_data = $this->upload->data();

}
于 2013-06-02T06:27:01.227 回答