我有一个包含来自我的数据库的内容的页面,但我希望能够显示这样的内容http://www.htmldrive.net/items/show/244/Amazon-style-image-and-title- scroller-with-jQuery我已经下载了脚本,并且(我认为)喜欢本教程,但它根本不起作用。我确定我在做一些愚蠢的事情,但我不知道是什么。
<link href="css/amazon_scroller.css" rel="stylesheet" type="text/css"></link>
<script type="text/javascript" src="js/jquery-1.3.2.min.js"></script>
<script type="text/javascript" src="js/amazon_scroller.js"></script>
<script language="javascript" type="text/javascript">
$(function() {
$("#amazon_scroller").amazon_scroller({
scroller_title_show: 'enable',
scroller_time_interval: '0',
scroller_window_background_color: "#CCC",
scroller_window_padding: '10',
scroller_border_size: '1',
scroller_border_color: '#000',
scroller_images_width: '150',
scroller_images_height: '100',
scroller_title_size: '12',
scroller_title_color: 'black',
scroller_show_count: '2',
directory: 'images'
});
});
</script>
<div id="amazon_scroller1" class="amazon_scroller">
<div class="amazon_scroller">
<div class="amazon_scroller_mask">
<ul>
<li>
<?php do { ?>
<div align="center" id="thumb"><a href="legendofgames/gameview.php?recordID=<?php echo $row_GameData['idGames']; ?>"><img src="../legendofgames/documentos/games/<?php echo $row_GameData['strImage']; ?>" width="165" height="120"/></a>
<div align="center" id="gametext"><?php echo $row_GameData['strNome']; ?> </div>
</div>
<?php } while ($row_GameData = mysql_fetch_assoc($GameData)); ?>
</div>
</li>
</ul>
</div>
<ul class="amazon_scroller_nav">
<li></li>
<li></li>
</ul>
<div style="clear: both"></div>
</div>