sql - 如何在触发器中插入值

Question

我试图在条件发生时插入一个值，但它给了我错误 ambiguos 列名，代码是：

create trigger B
on ALUNOS
after update, insert
as 
begin 
update ALUNOS
set média_final = 9 from inserted where média_final < 9
end  

Answer 1

try to follow this

update table set column = value where column = value

change value for the value that you want, you can add null or change null, don`t ever forget '' for string and lose it for numbers

Answer 2

create trigger B
on ALUNOS
after update, insert
as 
begin 
update ALUNOS
set média_final = 9 
from inserted i where i.média_final < 9
end  

模棱两可的列是 média_final，它在两个表中。指定它来自哪个表是您需要做的。