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我有这个字符串输出，我试图通过删除所有其余部分来获得输出值：1,0。

前任。

$ aplay -l | grep "C-Media USB Audio Device"
card 1: Device [C-Media USB Audio Device], device 0: USB Audio [USB Audio]

$ aplay -l | grep "C-Media USB Audio Device" | awk '{print $2}'
1:

$ aplay -l | grep "C-Media USB Audio Device" | awk '{print $9}'
0:

但是如何立即获得 1,0 的值？即使字符串有点大但在任何地方都有卡和设备？

例如：错

$ aplay -l
**** List of PLAYBACK Hardware Devices ****
card 0: PCH [HDA Intel PCH], device 0: CA0132 Analog [CA0132 Analog]
  Subdevices: 0/1
  Subdevice #0: subdevice #0
card 0: PCH [HDA Intel PCH], device 3: HDMI 0 [HDMI 0]
  Subdevices: 1/1
  Subdevice #0: subdevice #0
card 1: Device [C-Media USB Audio Device], device 0: USB Audio [USB Audio]
  Subdevices: 1/1
  Subdevice #0: subdevice #0
card 2: NVidia [HDA NVidia], device 3: HDMI 0 [HDMI 0]
  Subdevices: 1/1
  Subdevice #0: subdevice #0

$ aplay -l | grep "HDA NVidia" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'
2,0
$ aplay -l | grep "HDA Intel PCH" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'
0,CA0132
0,HDMI
$ aplay -l | grep "C-Media USB Audio Device" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'
1,0
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1 回答 1

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aplay -l | grep "C-Media USB Audio Device" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'

对于其他设备，它会删除[]和:char 之间的所有内容，

aplay -l | grep "C-Media USB Audio Device" | perl -nE 's/ \[.*?\] | : //xg; say join",",(split)[1,5];'
于 2013-05-31T07:45:09.047 回答