我希望这个函数在玩家 1 放置位置程序 chack 之后，左侧是玩家的 1 棋子以及玩家 1 的两个棋子之间的所有对手的爪子都打开“X”，就像在黑白棋游戏中一样。
这是整个未完成的代码：
#include<stdio.h>
#define SIZE 7
char board[SIZE][SIZE];
char letter;
int number;
void make_board(char tab[SIZE][SIZE]){
int w,k;
for(w=0; w < SIZE; w++){
for(k=0; k < SIZE; k++){
tab[w][k] = '.';
}
}
tab[0][0] = 'X';
tab[1][0] = '1';
tab[2][0] = '2';
tab[3][0] = '3';
tab[4][0] = '4';
tab[5][0] = '5';
tab[6][0] = '6';
tab[0][1] = 'A';
tab[0][2] = 'B';
tab[0][3] = 'C';
tab[0][4] = 'D';
tab[0][5] = 'E';
tab[0][6] = 'F';
tab[4][4] = 'X';
tab[4][3] = 'O';
tab[3][4] = 'O';
tab[3][3] = 'X';
}
char draw_board(char tab[SIZE][SIZE]){
int w, k;
for(w=0; w < SIZE; w++){
for(k=0; k < SIZE; k++){
printf("%2c", tab[w][k]);
}
printf("\n");
}
}
int translate(char letter){
int letter_to_number;
switch(letter){
case 'A':
case 'a':
letter_to_number = 1;
break;
case 'B':
case 'b':
letter_to_number = 2;
break;
case 'C':
case 'c':
letter_to_number = 3;
break;
case 'D':
case 'd':
letter_to_number = 4;
break;
case 'E':
case 'e':
letter_to_number = 5;
break;
}
return letter_to_number;
}
int finished(char tab[SIZE][SIZE]){ // looking '.' in array
int i,j;
for(i=1;i<=SIZE;i++){
for(j=1;j<=SIZE;j++){
if(tab[i][j]=='.'){
return 1;
}else{
return 0; // if don't find any '.' game is finish
}
}
}
}
void hit(char tab[SIZE][SIZE], int player ){
int i,j;
int *poz1, *poz2;
printf("Call out a letter and a number of a row and column on the grid:\n");
scanf(" %c %d", &letter, &number);
i=translate(letter);
poz1=&tab[number][i];
if(tab[number][i]=='.'){
if(player==1){
*poz1='X';
for(poz1-1;*poz1=='X';poz1--){
poz2=&poz1;}
poz1=&tab[number][i];
for(poz2;poz2<=poz1;poz2++){
*poz2='X';}
}else{
*poz1='O';
for(poz1-1;*poz1=='O';poz1--){
poz2=&poz1;}
poz1=&tab[number][i];
for(poz2;poz2<=poz1;poz2++){
poz2='O';}
}
}else{
printf("On this place already is pawn\n");
}
draw_board(board);
getchar();
}
int main(){
int i,j,k, pg1=0, pg2=0, player=1;
make_board(board);
draw_board(board);
do{
if(player==1){
printf("Player 1\n");
hit(board, gracz);
k=finished(board);
gracz=2;
}else{
printf("Player 2\n");
hit(board, gracz);
k=finished(board);
player=1;
}
}while(k==1);
for(i=1;i<=SIZE;i++){
for(j=1;j<=SIZE;j++){
if(board[i][j]=='X'){
pg1++;
}else{
pg2++;
}
}
}
if(pg1>pg2){
printf("Player 1 wins");
}else{
printf("Player 2 wins");
}
return 0;
}