所以,我有一个非常基本的测试设置,看看我是否可以将数据从 php 网页发送到运行在同一台服务器上的 java 应用程序。
Java 应用程序非常简单,它只是在 TCP 套接字上侦听数据
import java.io.*;
import java.net.*;
class TCPServer
{
public static void main(String argv[]) throws Exception
{
String clientSentence;
String capitalizedSentence;
ServerSocket welcomeSocket = new ServerSocket(6789);
while(true)
{
Socket connectionSocket = welcomeSocket.accept();
BufferedReader inFromClient =
new BufferedReader(new InputStreamReader(connectionSocket.getInputStream()));
DataOutputStream outToClient = new DataOutputStream(connectionSocket.getOutputStream());
clientSentence = inFromClient.readLine();
System.out.println("Received: " + clientSentence);
capitalizedSentence = clientSentence.toUpperCase() + '\n';
outToClient.writeBytes(capitalizedSentence);
connectionSocket.close(); //this line was part of the solution
}
}
}
我尝试了两种使用 php 发送和读取响应的方法,但似乎都不起作用。我的连接正常,数据发送正常,但是服务器没有打印任何东西,也没有响应任何东西,所以我不知道为什么它说没问题 :)
方法一
$host = "tcp://localhost";
$port = 6789;
$data = 'test' . PHP_EOL; //Adding PHP_EOL was the other part of the solution
$errstr = '';
$errno = '';
if ( ($fp = fsockopen($host, $port, $errno, $errstr, 3) ) === FALSE)
echo "$errstr ($errno)";
else {
print 'SUCCESS!<br />';
fwrite($fp, $data);
while (! feof($fp)) {
echo fgets($fp, 4096);
}
fclose($fp);
}
方法二
$host = "localhost";
$port = 6789;
$data = 'test';
if ( ($socket = socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) === FALSE )
echo "socket_create() failed: reason: " . socket_strerror(socket_last_error());
else
{
echo "Attempting to connect to '$host' on port '$port'...<br>";
if ( ($result = socket_connect($socket, $host, $port)) === FALSE )
echo "socket_connect() failed. Reason: ($result) " . socket_strerror(socket_last_error($socket));
else {
echo "Sending data...<br>";
socket_write($socket, $data, strlen($data));
echo "OK<br>";
echo "Reading response:<br>";
while ($out = socket_read($socket, 2048)) {
echo $out;
}
}
socket_close($socket);
}
编辑
显然 fsockopen() 从我在PHP fsockopen 发现的评论中连接到 localhost 时出现问题 fsockopen 没有返回任何内容,因此更改为 127.0.0.1 但仍然无法正常工作。