-2

I have a table being generated with results from a MySQL query. The table was generating fine until I tried to add an 'if else' statement. Now I get this error and have tried to troubleshoot but can't make it work.

"Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING"

This is the php code

<table>

<?php
foreach ($result AS $row) {

printf('
<tr>
<td>');

if(!empty($row['url']))

{
printf('
<img class="parklogo" border="0" src="/images/logos/%s" alt="%s" >' . 

PHP_EOL, $row['logo'], $row['logo']');
}

else
{
printf('
<img src="/images/%s%s-thumb.jpg" alt="%s"/>' . PHP_EOL, $row['url'], 

$row['alt'], $row['alt']');
}

printf('
</td>

<td>
%s<br>
%s<br>
%s

</td>

</tr>

' . PHP_EOL, $row['headline'], $row['Displaydate'],
$row['story'] );

}
?>

</table>

Any ideas what I've done wrong?

4

3 回答 3

2

改变这个: -

PHP_EOL, $row['logo'], $row['logo']'); 

PHP_EOL, $row['logo'], $row['logo']);  // removed the last single quote
于 2013-05-30T12:26:08.677 回答
2

删除行中的最后一个引号。

PHP_EOL, $row['logo'], $row['logo']');

$row['alt'], $row['alt']'

PHP_EOL, $row['logo'], $row['logo']);

$row['alt'], $row['alt']

于 2013-05-30T12:26:10.027 回答
2

改变这个

printf('<img class="parklogo" border="0" src="/images/logos/%s" alt="%s" >' . PHP_EOL, $row['logo'], $row['logo']');

printf('<img class="parklogo" border="0" src="/images/logos/%s" alt="%s" >' . PHP_EOL, $row['logo'], $row['logo']);
于 2013-05-30T12:26:20.150 回答