我有用于将文件上传到 PHP Web 服务的 ac# 函数。PHP Web 服务期待以下内容
- 一个名为 UploadFileRequestDto 的 POST 参数，其中包含一些 XML 数据
- 文件流
由于某些奇怪的原因，$_POST 参数仅在某些时候包含 UploadFileRequestDto。如果我看一下内容
file_get_contents("php://input"))
我可以看到请求正在按预期通过 UploadFileRequestDto 包括在内。
做一个
print_r($_REQUEST)
正在返回一个空数组。
谁能帮我解决这个问题，我的C#函数如下规定
public string UploadFile(UploadFileRequestDto uploadFileRequestDto,string fileToUpload, string fileUploadEndpoint)
{
try
{
var request = (HttpWebRequest)WebRequest.Create(fileUploadEndpoint);
request.ReadWriteTimeout = 1000 * 60 * 10;
request.Timeout = 1000 * 60 * 10;
request.KeepAlive = false;
var boundary = "B0unD-Ary";
request.ContentType = "multipart/form-data; boundary=" + boundary;
request.Method = "POST";
var postData = "--" + boundary + "\r\nContent-Disposition: form-data;";
postData += "name=\"UploadFileRequestDto\"\r\n\r\n";
postData += string.Format("{0}\r\n", SerializeUploadfileRequestDto(uploadFileRequestDto));
postData += "--" + boundary + "\r\n";
postData += "--" + boundary + "\r\nContent-Disposition: form-data;name=\"file\";filename=\"" + Path.GetFileName(fileToUpload) + "\"\r\n";
postData += "Content-Type: multipart/form-data\r\n\r\n";
var byteArray = Encoding.UTF8.GetBytes(postData);
byte[] boundaryBytes = Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");
byte[] filedata = null;
using (var reader = new BinaryReader(File.OpenRead(fileToUpload)))
{
filedata = reader.ReadBytes((int)reader.BaseStream.Length);
}
request.ContentLength = byteArray.Length + filedata.Length + boundaryBytes.Length;
request.GetRequestStream().Write(byteArray, 0, byteArray.Length);
request.GetRequestStream().Write(filedata, 0, filedata.Length);
request.GetRequestStream().Write(boundaryBytes, 0, boundaryBytes.Length);
var response = request.GetResponse();
var data = response.GetResponseStream();
var sReader = new StreamReader(data);
var sResponse = sReader.ReadToEnd();
response.Close();
return sResponse.TrimStart(new char[] { '\r', '\n' });
}
catch (Exception ex)
{
LogProvider.Error(string.Format("OzLib.Infrastructure : WebHelper : public string UploadFile(UploadFileRequestDto uploadFileRequestDto, string fileUploadEndpoint) : Exception = {0}", ex.ToString()));
}