它在示例中被装箱,对吗?
scala> typeOnly[java.lang.Double](vs)
res1: Seq[Double] = List(2.3)
更新:预言是适当的神秘: “拳击应该是不可见的,加号或减号”。我不知道这种情况是正还是负。
我的感觉是它是一个错误,因为否则它就是一个空的游戏。
更多 Delphic 的反对意见:“我不知道给定的示例会做什么。” 请注意,它未指定,预期由谁指定。
这是一个有用的练习,可以询问谁知道盒装,盒是什么?就好像编译器是一个魔术师,努力隐藏一根电线,让一张扑克牌悬浮在半空中,尽管每个观看的人都知道必须有一根电线。
scala> def f[A](s: Seq[Any])(implicit t: ClassTag[A]) = s collect {
| case v if t.runtimeClass.isPrimitive &&
| ScalaRunTime.isAnyVal(v) &&
| v.getClass.getField("TYPE").get(null) == t.runtimeClass =>
| v.asInstanceOf[A]
| case t(x) => x
| }
f: [A](s: Seq[Any])(implicit t: scala.reflect.ClassTag[A])Seq[A]
scala> f[Double](List(1,'a',(),"hi",2.3,4,3.14,(),'b'))
res45: Seq[Double] = List(2.3, 3.14)
ScalaRunTime
不支持 API - 调用isAnyVal
只是类型的匹配;也可以只检查“类型”字段是否存在或
Try(v.getClass.getField("TYPE").get(null)).map(_ == t.runtimeClass).getOrElse(false)
但是要回到一个不错的单线,你可以自己滚动ClassTag
来处理特殊情况下的提取。
2.11 版本。这可能不是最前沿的,但它是最近烧灼的边缘。
object Test extends App {
implicit class Printable(val s: Any) extends AnyVal {
def print = Console println s.toString
}
import scala.reflect.{ ClassTag, classTag }
import scala.runtime.ScalaRunTime
case class Foo(s: String)
val vs = List(1,'a',(),"hi",2.3,4,Foo("big"),3.14,Foo("small"),(),null,'b',null)
class MyTag[A](val t: ClassTag[A]) extends ClassTag[A] {
override def runtimeClass = t.runtimeClass
/*
override def unapply(x: Any): Option[A] = (
if (t.runtimeClass.isPrimitive && (ScalaRunTime isAnyVal x) &&
x.getClass.getField("TYPE").get(null) == t.runtimeClass)
Some(x.asInstanceOf[A])
else super.unapply(x)
)
*/
override def unapply(x: Any): Option[A] = (
if (t.runtimeClass.isPrimitive) {
val ok = x match {
case _: java.lang.Integer => runtimeClass == java.lang.Integer.TYPE
//case _: java.lang.Double => runtimeClass == java.lang.Double.TYPE
case _: java.lang.Double => t == ClassTag.Double // equivalent
case _: java.lang.Long => runtimeClass == java.lang.Long.TYPE
case _: java.lang.Character => runtimeClass == java.lang.Character.TYPE
case _: java.lang.Float => runtimeClass == java.lang.Float.TYPE
case _: java.lang.Byte => runtimeClass == java.lang.Byte.TYPE
case _: java.lang.Short => runtimeClass == java.lang.Short.TYPE
case _: java.lang.Boolean => runtimeClass == java.lang.Boolean.TYPE
case _: Unit => runtimeClass == java.lang.Void.TYPE
case _ => false // super.unapply(x).isDefined
}
if (ok) Some(x.asInstanceOf[A]) else None
} else if (x == null) { // let them collect nulls, for example
if (t == ClassTag.Null) Some(null.asInstanceOf[A]) else None
} else super.unapply(x)
)
}
implicit def mytag[A](implicit t: ClassTag[A]): MyTag[A] = new MyTag(t)
// the one-liner
def g[A](s: Seq[Any])(implicit t: ClassTag[A]) = s collect { case t(x) => x }
// this version loses the "null extraction", if that's a legitimate concept
//def g[A](s: Seq[Any])(implicit t: ClassTag[A]) = s collect { case x: A => x }
g[Double](vs).print
g[Int](vs).print
g[Unit](vs).print
g[String](vs).print
g[Foo](vs).print
g[Null](vs).print
}
对于 2.10.x,额外的样板代码行是因为隐式解析是——好吧,我们不会说它坏了,我们只会说它不起作用。
// simplified version for 2.10.x
object Test extends App {
implicit class Printable(val s: Any) extends AnyVal {
def print = Console println s.toString
}
case class Foo(s: String)
val vs = List(1,'a',(),"hi",2.3,4,Foo("big"),3.14,Foo("small"),(),null,'b',null)
import scala.reflect.{ ClassTag, classTag }
import scala.runtime.ScalaRunTime
// is a ClassTag for implicit use in case x: A
class MyTag[A](val t: ClassTag[A]) extends ClassTag[A] {
override def runtimeClass = t.runtimeClass
override def unapply(x: Any): Option[A] = (
if (t.runtimeClass.isPrimitive && (ScalaRunTime isAnyVal x) &&
(x.getClass getField "TYPE" get null) == t.runtimeClass)
Some(x.asInstanceOf[A])
else t unapply x
)
}
// point of the exercise in implicits is the type pattern.
// there is no need to neutralize the incoming implicit by shadowing.
def g[A](s: Seq[Any])(implicit t: ClassTag[A]) = {
implicit val u = new MyTag(t) // preferred as more specific
s collect { case x: A => x }
}
s"Doubles? ${g[Double](vs)}".print
s"Ints? ${g[Int](vs)}".print
s"Units? ${g[Unit](vs)}".print
s"Strings? ${g[String](vs)}".print
s"Foos? ${g[Foo](vs)}".print
}
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@WilfredSpringer 有人听到了。SI-6967