0

我在尝试迭代查询中返回的结果量时遇到问题，我有一个Cart使用以下字段调用的数据库表：

项目代码 //Unique Code of Item

项目描述 //Description / Name ofItem

商品单价 //Unit Price for Item

项目类别 //Category of Item e.g. Books, CD, DVD etc...

数量 //Quantity of Item(s) in cart

我想遍历显示在我的所有记录display.php（它只是打印Cart表中的所有数据），然后将每个项目乘以ItemUnitPrice并将Quantity其存储在一个变量中以存储display.php.

我想要这样的东西：

LOOP
$Total= $ItemUnitPrice * $Quantity;
END LOOP

我正在使用 MySQL，但我不太确定应该如何循环获取每个项目的总数。

所以简而言之，我想找到数据库表中每个项目的总数（ ItemUnitPrice* ）并将其存储在一个变量中。Quantity

编辑：

$query="SELECT * FROM Cart";
$result=mysql_query($query);
$num=mysql_num_rows($result);


$cartTotalPrice = 0;

while($row = mysql_fetch_assoc($result))
{
$cartTotalPrice += ($row['itemUnitPrice']*$row['Quantity']);

}
$_SESSION['totalCost'] = $cartTotalPrice;
mysql_close();
session_start();
echo "<b><center> Islamic Book Store - Your Shopping Cart </b><br/><br/>";

$i=0;

echo "<table border=1><tr><th>Item Code</th><th>Item Desc,</th>";
echo "<th> Item Unit Price</th><th>Item Category</th><th>Quantity</th><th>Image</th>    <th>Update Quantity</th></tr>";

while ($i < $num)

{

$ItemCode = mysql_result($result,$i,"ItemCode");
$ItemDesc = mysql_result($result,$i,"ItemDesc");
$ItemUnitPrice = mysql_result($result,$i,"ItemUnitPrice");
$ItemCategory = mysql_result($result,$i,"ItemCategory");
$Quantity = mysql_result($result,$i,"Quantity");


echo "<tr><td align=center>$ItemCode</td><td align=center>$ItemDesc</td>";
echo "<td align=center>£$ItemUnitPrice</td>";
echo "<td align=center>$ItemCategory</td><td align=center>$Quantity</td>";

$i++;

}



echo "</table><center>";
echo "$num Item(s) found.";

echo "<br/><br/><center><form action = 'clear.php'><input type='submit' value='Clear'>   </form></center>";



?>



<html>
<form action="https://www.paypal.com/cgi-bin/webscr" method="post" target="_BLANK">
<input type="hidden" name="cmd" value="_xclick" />
<input type="hidden" name="business" value="email@example.com" />
<input type="hidden" name="item_name" value="<? echo $ItemDesc ?>" />
<input type="hidden" name="item_number" value="TEST ITEM NUMBER" />
<input type="hidden" name="amount" value="<? echo $cartTotalPrice ?>" />
<input type="hidden" name="currency_code" value="GBP" />
<input type="hidden" name="lc" value="GB" />
<input type="hidden" name="bn" value="PP-BuyNowBF" />
<input src="paypal/purchase.png" name="Submit" type="image" value="purchase"    alt="Purchase" />
</form>
</html>
4

2 回答 2

1

首先要改掉使用mysql_*函数的习惯！使用PDO或mysqli。

为什么我不应该在 PHP 中使用 mysql_* 函数？

http://php.net/pdo

其次，我很遗憾地告诉你，你的代码完全错误！

session_start();

$query = "SELECT * FROM Cart";
$result = mysql_query($query);
$num = mysql_num_rows($result);

$cartTotalPrice = 0;

while($row = mysql_fetch_assoc($result))
{
    $cartTotalPrice += ($row['itemUnitPrice']*$row['Quantity']);

    echo "<tr><td align=center>{$row['itemCode']}</td><td align=center>{$row['ItemDesc']}</td>";
    echo "<td align=center>{$row['ItemUnitPrice']}</td>";
    echo "<td align=center>{$row['$ItemCategory']}</td><td align=center>{$row['$Quantity']}</td></tr>";
}

$_SESSION['totalCost'] = $cartTotalPrice;

// $_SESSION['totalCost'] is now available on every page (as long as you use start_session() before any output)

mysql_close();
于 2013-05-29T20:49:20.220 回答
0

试试下面的代码我希望它有效，我做了更正并在评论中提到它们：

$query="SELECT * FROM Cart";
$result=mysql_query($query);
$num=mysql_num_rows($result);


$cartTotalPrice = 0;

while($row = mysql_fetch_assoc($result))
{
$cartTotalPrice += ($row['itemUnitPrice']*$row['Quantity']);

}


 session_start();
 $_SESSION['totalCost'] = $cartTotalPrice;
   // mysql_close(); // here you are closing your mysql connection before using mysql_result refer to the example in http://php.net/manual/en/function.mysql-result.php
   // session_start(); // session start should go above  you dont need session if the whole script is in the same page. no need to save the variable to session
echo "<b><center> Islamic Book Store - Your Shopping Cart </b><br/><br/>";

$i=0;

echo "<table border=1><tr><th>Item Code</th><th>Item Desc,</th>";
echo "<th> Item Unit Price</th><th>Item Category</th><th>Quantity</th><th>Image</th>    <th>Update Quantity</th></tr>";

while ($i < $num)

{

$ItemCode = mysql_result($result,$i,"ItemCode");
$ItemDesc = mysql_result($result,$i,"ItemDesc");
$ItemUnitPrice = mysql_result($result,$i,"ItemUnitPrice");
$ItemCategory = mysql_result($result,$i,"ItemCategory");
$Quantity = mysql_result($result,$i,"Quantity");


echo "<tr><td align=center>$ItemCode</td><td align=center>$ItemDesc</td>";
echo "<td align=center>£$ItemUnitPrice</td>";
echo "<td align=center>$ItemCategory</td><td align=center>$Quantity</td>";

$i++;

}



echo "</table><center>";
echo "$num Item(s) found.";

echo "<br/><br/><center><form action = 'clear.php'><input type='submit' value='Clear'>   </form></center>";


mysql_close();
?>



<html>
<form action="https://www.paypal.com/cgi-bin/webscr" method="post" target="_BLANK">
<input type="hidden" name="cmd" value="_xclick" />
<input type="hidden" name="business" value="info@asianweddingservices.org" />
<input type="hidden" name="item_name" value="<? echo $ItemDesc ?>" />
<input type="hidden" name="item_number" value="TEST ITEM NUMBER" />
<input type="hidden" name="amount" value="<? echo $cartTotalPrice ?>" />
<input type="hidden" name="currency_code" value="GBP" />
<input type="hidden" name="lc" value="GB" />
<input type="hidden" name="bn" value="PP-BuyNowBF" />
<input src="paypal/purchase.png" name="Submit" type="image" value="purchase"    alt="Purchase" />
</form>
</html>
于 2013-05-30T23:51:07.623 回答