我会建议一些类似的东西,因为所需的嵌套深度和样板代码的数量低于建议的解决方案。但是,实际参数包永远不会拆分,而是生成两个索引范围来索引输入值,这些输入值作为元组转发,然后通过 std::get 访问。除了嵌套深度之外,更容易指定如何执行拆分(向上、向下舍入或取 2 的幂和余数)。
int sum(int a) { return a; }
int sum(int a, int b) { return a + b; }
template<typename... Args> int sum(Args&&... args);
template<typename Tuple, size_t... index>
int sum_helper(pack_indices<index...>, Tuple&& args)
{
return sum(std::get<index>(args)...);
}
template <size_t begin, size_t end, typename... Args>
int sum_helper(Args&&... args)
{
typename make_pack_indices<end, begin>::type indices;
return sum_helper(indices, std::forward_as_tuple(std::forward<Args>(args)...));
}
template<typename... Args>
int sum(Args&&... args)
{
constexpr size_t N = sizeof...(Args);
return sum(
sum_helper<0, N/2>(std::forward<Args>(args)...),
sum_helper<N/2, N>(std::forward<Args>(args)...)
);
}
这需要
template <size_t...>
struct pack_indices {};
template <size_t Sp, typename IntPack, size_t Ep>
struct make_indices_imp;
template <size_t Sp, size_t Ep, size_t... Indices>
struct make_indices_imp<Sp, pack_indices<Indices...>, Ep>
{
typedef typename make_indices_imp<Sp+1, pack_indices<Indices..., Sp>, Ep>::type type;
};
template <size_t Ep, size_t... Indices>
struct make_indices_imp<Ep, pack_indices<Indices...>, Ep>
{
typedef pack_indices<Indices...> type;
};
template <size_t Ep, size_t Sp = 0>
struct make_pack_indices
{
static_assert(Sp <= Ep, "make_tuple_indices input error");
typedef typename make_indices_imp<Sp, pack_indices<>, Ep>::type type;
};