3

单击微调器时出现问题（在弹出窗口中）

这是我的弹出窗口：

public class PopupDialog extends PopupWindow  {

    public PopupDialog() {
        super();
        init();
    }

    public PopupDialog(View contentView, int width, int height) {
        super(contentView, width, height);
        init();
    }

    public PopupDialog(View contentView) {
        super(contentView);
        init();
    }

    private void init() {
        this.setTouchable(true);
        this.setFocusable(true);
        this.setOutsideTouchable(true);
        setBackgroundDrawable(new BitmapDrawable());

        this.setTouchInterceptor(new OnTouchListener() {
            @Override
            public boolean onTouch(View v, MotionEvent event) {
                if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {
                    PopupDialog.this.dismiss();

                    return true;
                }

                return false;
            }
        });

    }

}

单击显示弹出窗口的按钮：

public void click(View v) {
        LayoutInflater layoutInflater 
         = (LayoutInflater)getBaseContext()
          .getSystemService(LAYOUT_INFLATER_SERVICE);  
        View popupView = layoutInflater.inflate(R.layout.popup, null);  
                 final PopupDialog popupWindow = new PopupDialog(
                   popupView, 
                   LayoutParams.WRAP_CONTENT,  
                         LayoutParams.WRAP_CONTENT);

                 DisplayMetrics metrics = new DisplayMetrics();
                 getWindowManager().getDefaultDisplay().getMetrics(metrics);
                 popupWindow.setHeight(metrics.heightPixels);
                 popupWindow.setWidth(300);

                 popupWindow.showAtLocation(v, Gravity.NO_GRAVITY, v.getLeft()+v.getWidth(), 0);

    }

我有这个异常（ BadTokenException ）

05-29 16:35:10.627: E/AndroidRuntime(1055): FATAL EXCEPTION: main
05-29 16:35:10.627: E/AndroidRuntime(1055): android.view.WindowManager$BadTokenException: Unable to add window -- token android.view.ViewRootImpl$W@410ad298 is not valid; is your activity running?
05-29 16:35:10.627: E/AndroidRuntime(1055):     at android.view.ViewRootImpl.setView(ViewRootImpl.java:515)
05-29 16:35:10.627: E/AndroidRuntime(1055):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:279)
05-29 16:35:10.627: E/AndroidRuntime(1055):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:193)
05-29 16:35:10.627: E/AndroidRuntime(1055):     at android.view.WindowManagerImpl$CompatModeWrapper.addView(WindowManagerImpl.java:118)
05-29 16:35:10.627: E/AndroidRuntime(1055):     at android.view.Window$LocalWindowManager.addView(Window.java:537)
05-29 16:35:10.627: E/AndroidRuntime(1055):     at android.widget.PopupWindow.invokePopup(PopupWindow.java:988)
05-29 16:35:10.627: E/AndroidRuntime(1055):     at and

欢迎任何帮助，提前谢谢你:)

4

3 回答 3

9

存在上下文冲突。尝试在您的 XML 微调器声明中添加它：android:spinnerMode="dialog"

于 2013-09-13T08:07:01.817 回答
0

在这里做一个测试，

暂时删除这部分代码

 this.setTouchInterceptor(new OnTouchListener() {
            @Override
            public boolean onTouch(View v, MotionEvent event) {
                if (event.getAction() == MotionEvent.ACTION_OUTSIDE) {
                    PopupDialog.this.dismiss();

                    return true;
                }

                return false;
            }
        });

并检查。

于 2013-05-29T17:08:58.000 回答
0

我希望现在还不算晚。我遇到过同样的问题。事情进展顺利

android:spinnerMode="dialog"

但是，我无法使用 PopupWindow 实现下拉菜单（没有弹出对话框）。我通过使用alertbuilder得到了同样的工作。

您可以按照本教程进行操作： YT Link

于 2018-04-05T19:29:05.663 回答