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我已经用谷歌搜索试图找到答案，但没有。

我正在创建一个站点，用户可以在其中搜索并使用谷歌地理编码 api 选择一个地方，然后我得到那个地方的范围，但是用户应该能够增加这些范围。

例如，用户可以在 5 公里内增加与那个地方的距离，所以我可以在 5 公里内增加边界。

这是用户搜索某个地方时的结果：

"geometry" : {
        "bounds" : {
           "northeast" : {
              "lat" : 42.15420480,
              "lng" : -6.19020910
           },
           "southwest" : {
              "lat" : 32.403740,
              "lng" : -31.2751580
           }
        },

现在我需要增加 5 公里的界限。考虑到我必须将公里转换为度数，我怎么能在 javascript 中做到这一点？

非常感谢。

编辑

感谢@geocodezip，我尝试了这个，但有些东西不是qorking。我尝试按照此处“给定距离和距起点的方位的目标点”的说明进行尝试，但是有些工作不正常。这是代码：

//convert decimal to degree
function getDD2DMS(dms, type){
    var sign = 1, Abs=0;
    var days, minutes, secounds, direction;

    if(dms < 0)  { sign = -1; }
    Abs = Math.abs( Math.round(dms * 1000000.));
    //Math.round is used to eliminate the small error caused by rounding in the computer:
    //e.g. 0.2 is not the same as 0.20000000000284
    //Error checks
    if(type == 'lat' && Abs > (90 * 1000000)){
        //alert(' Degrees Latitude must be in the range of -90. to 90. ');
        return false;
    } else if(type == 'lng' && Abs > (180 * 1000000)){
        //alert(' Degrees Longitude must be in the range of -180 to 180. ');
        return false;
    }
    days = Math.floor(Abs / 1000000);
    minutes = Math.floor(((Abs/1000000) - days) * 60);
    secounds = ( Math.floor((( ((Abs/1000000) - days) * 60) - minutes) * 100000) *60/100000 ).toFixed();
    days = days * sign;
    if(type == 'lat') direction = days<0 ? 'S' : 'N';
    if(type == 'lng') direction = days<0 ? 'W' : 'E';
    //else return value     
    return (days * sign) + 'º ' + minutes + "' " + secounds + "'' " + direction;
}

//calculate
    var R = 6371; // km
    var d = 10; //km
    var brng = 0; //0 vertical, 90 horizontal
    var lat1 = (42.15420480).toRad();
    var lon1 = (-6.19020910).toRad();
    var lat2 = Math.asin( Math.sin(lat1)*Math.cos(d/R) + Math.cos(lat1)*Math.sin(d/R)*Math.cos(brng) );
    var lon2 = lon1 + Math.atan2(Math.sin(brng)*Math.sin(d/R)*Math.cos(lat1), Math.cos(d/R)-Math.sin(lat1)*Math.sin(lat2));

    console.log('lat2 = ' + getDD2DMS(lat2, 'lat'));
    console.log('lon2 = ' + getDD2DMS(lon2, 'lng'));

结果与链接不一样。帮我。非常感谢。

4

1 回答 1

0

我不完全理解您的问题，但您可以尝试绘制一个边界框并使用边界作为偏差发送搜索。

var bounds;
google.maps.event.addListener(drawingManager, 'rectanglecomplete', function (rectangle) {
     bounds = rectangle.getBounds();
     //search
     google.maps.event.addListener(rectangle, 'bounds_changed', function () {
            bounds = rectangle.getBounds();
            //search
     }
}

//this is a copy of the search function in my app
function codeAddress(type, geo) {
var bounds = map.getBounds(); //get the current map bounds (should not be greater than the bounding box)
geocoder.geocode({ 'address': geo, 'bounds': bounds }, function (results, status) { //geocode the lat/long of incoming with a bias towards the bounds
    if (status == google.maps.GeocoderStatus.OK) { //if it worked
        map.setCenter(results[0].geometry.location); //set the center of map to the results
        testBounds(); //test to make sure we are indeed in the bounds (have to do this because gmaps only allows for a BIAS of bounds and is not strict)
        if (mapInBounds == "yes") { //if it is inside bounds
            if (searchCount > 0) { //check to see if this is the first time searched, if not
                searchResult.setMap(null); //set old search result to not display on map
            } else { //if it is the first time
                searchCount++; //just interate
            }
            searchResult = new google.maps.Marker({ //create a new marker
                map: map, //add to current map
                position: results[0].geometry.location //set position to search results
            });
            document.getElementById("search_results").innerHTML = "<div id=\"searchResult\">" + geo + " <a href=\"#\" onclick=\"searchResultDeleteMe();\"><img src=\"images/delete.png\"/></a></div><br\>"; //add list div
        } else { //if location found was outside strict map bounds...
            displayMessage("Could not find within bounds."); //say so
        }

    } else { //if the entire geocode did not work
        alert(L6); //localization...
    }
});
}               //get the location of a lat/long or address
function codeLatLng(latlng) {
if (geocoder) {
    geocoder.geocode({ 'latLng': latlng }, function (results, status) {
        if (status == google.maps.GeocoderStatus.OK) {
            if (results[1]) {
                document.getElementById("rgItem").innerHTML = results[0].formatted_address;
            }
            else {
                document.getElementById("rgItem").innerHTML = "Geocoder failed due to: " + status;
                document.getElementById("rgItem").innerHTML = "";
            }
        }
    });
}
}                   //get th
于 2013-05-29T14:00:02.817 回答