php - 加载值ajax响应

Question

我正在尝试在两个不同的 div 中获取数据，但问题是当我在第二个 div 中选择 make 选项时，第二个 div 没有响应模型，它从第一个 div 中选择模型。如何格式化此代码.... .

<div id="col1"> 
    <table width="20%" border="0" cellpadding="4" cellspacing="0" id="tbsrch-engine14"> 
        <tr>
            <td height="10">
                <strong>Make:</strong> 
            </td>
            <td>
                <select name="make" id="make" style="width: 155px;" onChange="get_models(this.value,'<?php echo $base_url ?>ajaxResponse/get_models.php')"> 
                    <option value="0">Any</option> 
                    <?php 
                        $query = "SELECT id, name FROM tbl_make";
                        $result = mysql_query($query);
                    ?> 
                    <?php while ( $row = mysql_fetch_array($result)) {?> 
                        <option value="<?php echo $row['id'].'-'.$row['name']?>">
                            <?php echo $row['name']?>
                        </option> 
                    <?php }?> 
                </select> 
            </td> 
        </tr> 
        <tr> 
            <td height="40"> 
                <strong>Model:</strong> 
            </td> 
            <td> 
                <div id="models">
                    <select name="model" id="model"> 
                        <option value="0">Any</option>
                    </select> 
                </div> 
            </td> 
        </tr> 
        </tbody> 
    </table> 
</div> 
<div id="col2">
    <table width="100%" border="0" cellpadding="6" cellspacing="0" id="tbsrch-engine13"> 
        <tbody> 
            <tr> 
                <td height="10px;"> 
                    <select name="make" id="make" style="width: 155px;" onChange="get_models(this.value,'<?php echo $base_url ?>ajaxResponse/get_models.php')"> 
                        <option value="0">Any</option> 
                        <?php 
                        $query = "SELECT id, name FROM tbl_make ";
                        $result = mysql_query($query); ?> 
                        <?php while ( $row = mysql_fetch_array($result)) {?> 
                            <option value="<?php echo $row['id'].'-'.$row['name']?>"><?php echo $row['name']?></option>
                        <?php }?> 
                    </select> 
                </td> 
            </tr> 
            <tr> 
                <td> 
                    <div id="models"> 
                        <select name="model" id="model"> 
                            <option value="0">Any</option> 
                        </select>
                    </div> 
                </td> 
            </tr> 
        </tbody> 
    </table> 
</div>