9

使用 2 个参数执行 POST 请求时：

return $this->perform($client->post("/authenticate",null, array(
  "username" => 'radupass',
  "password" => '@alcool', //starting with an @
)));

$客户端：

/**
* @return \Guzzle\Service\Client
*/
public function getClient()
{
  if ($this->_client === null) {
    $this->_client = new Guzzle\Service\Client($this->baseUrl, $this->_options);
    $this->_client->setDefaultHeaders(array(
      "X-WebsiteId" => $this->websiteId,
      "X-AccessToken" => $this->accessToken,
    ));
}
return $this->_client;
}

我得到以下异常：

2013/05/29 11:08:29 [error] [exception.Guzzle\Common\Exception\InvalidArgumentException] exception 'Guzzle\Common\Exception\InvalidArgumentException' with message 'Unable to open lcool for reading' in /home/xxx/site/vendor/guzzle/guzzle/src/Guzzle/Http/Message/PostFile.php:58
Stack trace:
#0 /home/xxx/site/vendor/guzzle/guzzle/src/Guzzle/Http/Message/PostFile.php(25): Guzzle\Http\Message\PostFile->setFilename('@lcool')
#1 /home/xxx/site/vendor/guzzle/guzzle/src/Guzzle/Http/Message/EntityEnclosingRequest.php(245): Guzzle\Http\Message\PostFile->__construct('password', '@lcool', NULL)
#2 /home/xxx/site/vendor/guzzle/guzzle/src/Guzzle/Http/Message/EntityEnclosingRequest.php(273): Guzzle\Http\Message\EntityEnclosingRequest->addPostFile('password', '@lcool', NULL, false)
#3 /home/xxx/site/vendor/guzzle/guzzle/src/Guzzle/Http/Message/RequestFactory.php(127): Guzzle\Http\Message\EntityEnclosingRequest->addPostFiles(Array)
#4 /home/xxx/site/vendor/guzzle/guzzle/src/Guzzle/Http/Client.php(256): Guzzle\Http\Message\RequestFactory->create('POST', 'http://api.subs...', Object(Guzzle\Common\Collection), Array)
#5 /home/xxx/site/vendor/guzzle/guzzle/src/Guzzle/Http/Client.php(336): Guzzle\Http\Client->createRequest('POST', '/authenticate', NULL, Array)
#6 /home/xxx/site/frontend/components/SubServerClient.php(117): Guzzle\Http\Client->post('/authenticate', NULL, Array)

似乎客户端正在尝试打开文件。

编辑

查看我看到的 Guzzle 源代码：

https://github.com/guzzle/guzzle/blob/master/src/Guzzle/Http/Message/RequestFactory.php#L88

 if (is_array($body) || $body instanceof Collection) {
                // Normalize PHP style cURL uploads with a leading '@' symbol
                foreach ($body as $key => $value) {
                    if (is_string($value) && substr($value, 0, 1) == '@') {
                        $request->addPostFile($key, $value);
                        unset($body[$key]);
                    }
                }
                // Add the fields if they are still present and not all files
                $request->addPostFields($body);
            }

如果我想逃避那个角色怎么办？

4

2 回答 2

4

似乎是 cURL 本身的一个已知问题：

在 PHP 中使用 CURL 发布以“@”开头的文本数据

一种解决方案是使用百分比编码，而“@”符号将是“%40”，即使这需要一些额外的工作。

另请参阅此线程。

于 2013-05-29T11:57:38.270 回答
3

当您查看Guzzle Request Documentation时，您会发现所有以@sign 开头的 POST 参数都被视为文件路径。请参阅他们的文档中的示例：

$request = $guzzleClient->post($url, $headers, [
    'file_field'   => '@/path/to/file.xml'
]);

我通过setPostField()分配 POST 参数的方法解决了这个问题，这是我的示例：

$request = $guzzleClient->post($url, $headers);
foreach ($postData as $key => $value) {
    $request = $request->setPostField($key, $value);
}
$guzzleClient->send($request);
于 2015-11-10T16:42:10.920 回答