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我需要建立一个联系人选择器，其中列出了除帐户类型的联系人之外的所有电话联系人。我确实遵循了这种方式：示例我要从列表中删除的帐户类型是：group = "com.account.myaccount"

首先，我查询所有组 id 的帐户类型：

    public String[] getGroupIds(Context context, String group){
    
    final Cursor groupCursor = context.getContentResolver().query(
            GroupWrap.CONTENT_URI,
            GroupWrap.PROJECTION,
            GroupWrap.SELECTION_GROUP_ID,
            new String[]{group},
            null);

    String[] ids = new String[groupCursor.getCount()];
    int i = 0;
    final int contactNumberColumnType   = groupCursor.getColumnIndex(GroupWrap.COLUMN_TYPE); 
    final int contactNumberColumnIndex  = groupCursor.getColumnIndex(GroupWrap.COLUMN_ID);
    
    
    while (groupCursor.moveToNext()) {
        ids[i++] = Integer.toString(groupCursor.getInt(contactNumberColumnIndex));
        
        Log.v(TAG, " account type : " + groupCursor.getString(contactNumberColumnType)
                 + " : ids[]" + groupCursor.getInt(contactNumberColumnIndex)); 
                 
    }
    
    

    return ids;
}

final private static class GroupWrap {

    private GroupWrap() {
    }

    public static final String[] PROJECTION =
            new String[] {Groups.ACCOUNT_TYPE, Groups._ID};

    public static final String COLUMN_TYPE = Groups.ACCOUNT_TYPE;
    public static final String COLUMN_ID = Groups._ID;
    public static final Uri CONTENT_URI = Groups.CONTENT_URI;
    public static final String SELECTION_OTHER_GROUP_ID = GroupWrap.COLUMN_TYPE + "!=?";
    public static final String SELECTION_GROUP_ID = GroupWrap.COLUMN_TYPE + "=?";
}

然后我查询除组之外的所有联系人：

    public  Cursor getContactGroupIDs(String[] groupIds, Context context){
    
    String selection = ContactsQuery.COLUMN_NAME + " NOTNULL) AND ("

            + ContactsQuery.COLUMN_NAME + " !='' ) AND ";

    StringBuffer buffer = new StringBuffer(selection); 

    for(int i = 0; i < groupIds.length; i++){
        buffer.append(" (" + GroupMembership.GROUP_ROW_ID + " !=?) AND ");
    }


    // remove " ) AND "
    if(buffer.length() > 0){
        buffer.delete(buffer.length() - 6, buffer.length());
    }

    
    selection = buffer.toString();
    
    Log.v(TAG, "selection : " + selection);
    
    String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
    
    Cursor cursor = context.getContentResolver().query(ContactsQuery.CONTENT_URI, 
            ContactsQuery.PROJECTION, selection, groupIds, sortOrder);
    
    return cursor;
}


final public static class ContactsQuery {

    private ContactsQuery() {
        
    }

    public static final String COLUMN_NAME = Data.DISPLAY_NAME;
    public static final String COLUMN_ID = Data._ID;
    public static final String COLUMN_CONTACT_ID = Data.CONTACT_ID;
    public static final Uri CONTENT_URI = Data.CONTENT_URI;
    
    public static final String[] PROJECTION =
            new String[] {COLUMN_NAME, COLUMN_CONTACT_ID};

}

并结合所有：

    public List<PickerContactRow> getContactExceptGroup(Context context, String group){
    String[] groupIds = getGroupIdsExcept(context, group);
    List<PickerContactRow> result = new ArrayList<PickerContactRow>();
    
    Set<Long> seen = new HashSet<Long>();
    
    Cursor cursor = this.getContactGroupIDs(groupIds, context);
    
    
    int indexOfContactId = cursor.getColumnIndex(ContactsQuery.COLUMN_CONTACT_ID);
    int indexOfName = cursor.getColumnIndex(ContactsQuery.COLUMN_NAME);

    
    while (cursor.moveToNext()) {
        long contactID = cursor.getLong(indexOfContactId);
        if (!seen.contains(contactID)) {// remove duplicate contact
            seen.add(contactID);
            PickerContactRow contactRow = new PickerContactRow();
            contactRow.setId(contactID);
            contactRow.setName(cursor.getString(indexOfName));
            
            Log.v(TAG, "row : " + contactRow); 
                    //+ "group : " + cursor.getString(columnGroup));
            
            result.add(contactRow);
        }
    }
    
    return result;
}

问题是显示了一些奇怪的帐户名。一些电子邮件而不是帐户名。看我的图片：

在此处输入图像描述

请帮我解决问题。或者您有任何其他方法来过滤帐户。我正在寻找可以使用 CursorAdapter 的解决方案。我的方法不能使用 CursorAdapter。

4

1 回答 1

1

我自己解决了。我确实是这样流动的：

public  Cursor getContactGroupIDs(String acountType, Context context){

    String sortOrder = ContactsQuery.COLUMN_NAME + " COLLATE LOCALIZED ASC";

    Cursor cursor = context.getContentResolver().query(ContactsQuery.CONTENT_URI, 
            ContactsQuery.PROJECTION, ContactsQuery.SELECTION , null, sortOrder);

    return cursor;
}

private boolean isAccountType(Context context, String accountType, long id){
    Cursor cursor = context.getContentResolver().query(RawContactsQuery.CONTENT_URI, 
            RawContactsQuery.PROJECTION, RawContactsQuery.SELECTION , new String[]{id + "", accountType}, null);
    boolean result = cursor.getCount() > 0;
    cursor.close();
    return result;
}

public List<PickerContactRow> getContactExceptGroup(Context context, String accountType){
    List<PickerContactRow> result = new ArrayList<PickerContactRow>();

    Cursor cursor = this.getContactGroupIDs(accountType, context);
    EmailValidator validator = new EmailValidator();

    int indexOfContactId = cursor.getColumnIndex(ContactsQuery.COLUMN_CONTACT_ID);
    int indexOfName = cursor.getColumnIndex(ContactsQuery.COLUMN_NAME);
    final int columnGroup   = cursor.getColumnIndex(ContactsQuery.DELETED);

    while (cursor.moveToNext()) {
        long id = cursor.getLong(indexOfContactId);
        if (!isAccountType(context, accountType, id)) 
        {
            //seen.add(contactID);
            PickerContactRow contactRow = new PickerContactRow();
            contactRow.setId(id);
            contactRow.setName(cursor.getString(indexOfName));

            Log.v(TAG, "row : " + contactRow
                    + " value : " + cursor.getString(columnGroup));



            result.add(contactRow);
        }
    }
    cursor.close();
    return result;
}


final public static class ContactsQuery {

    private ContactsQuery() {

    }

    public static final String COLUMN_NAME = Contacts.DISPLAY_NAME;
    public static final String COLUMN_ID = Contacts._ID;
    public static final String DELETED = Contacts.HAS_PHONE_NUMBER;
    public static final String COLUMN_CONTACT_ID =  Contacts._ID;
    public static final Uri CONTENT_URI = Contacts.CONTENT_URI;
    public static final String SELECTION = COLUMN_NAME + " NOTNULL"
            + ") AND (" + COLUMN_NAME + " !=''"
             + ") AND (" + Contacts.HAS_PHONE_NUMBER + " =1";


    public static final String[] PROJECTION =
            new String[] {COLUMN_NAME, COLUMN_CONTACT_ID, DELETED};

}


final public static class RawContactsQuery {

    private RawContactsQuery() {

    }

    public static final String ACCOUNT_TYPE = RawContacts.ACCOUNT_TYPE;
    public static final String COLUMN_CONTACT_ID = RawContacts.CONTACT_ID;
    public static final Uri CONTENT_URI = RawContacts.CONTENT_URI;
    public static final String SELECTION = COLUMN_CONTACT_ID + "=?) AND (" + ACCOUNT_TYPE + " =?";

    public static final String[] PROJECTION =
            new String[] {COLUMN_CONTACT_ID};

}

我看到它很慢，但我找不到其他方法。

于 2013-05-30T03:57:06.077 回答