c# - 循环并在每次迭代c#中创建新的实例对象

Question

所以我试图创建一个循环，每次循环时我都会创建一个对象的新实例：像这样。

Client client = new Client(session);
client.Connect(server);

while (true) {
    client.SendPacket(new Craft.Net.CreativeInventoryActionPacket(-1, new Craft.Net.ItemStack((short)19, (sbyte)1)));

    client.Disconnect ("Generic");

    System.Threading.Thread.Sleep(3000);

    //obviously I cannot do this, because there is already an object named client.
    Client client = new Client(session);

    client.Connect(server);
}

我该怎么做呢？我需要创建一个新的 MinecraftClient 实例，在执行 client.Disconnect 后我无法重用旧实例。

Answer 1

最简单的工作就是改变

Client client = new Client(session);

至

client = new Client(session);

也就是说，我认为有一种更清洁的方法。从...开始：

while(true) {
    Client client = new Client(session);
    client.Connect(server);
    client.SendPacket (new Craft.Net.CreativeInventoryActionPacket(-1, new Craft.Net.ItemStack((short)19, (sbyte)1)));
    client.Disconnect ("Generic");
    System.Threading.Thread.Sleep(3000);
}

现在将其分解为一个方法：

private void ConnectAndDoStuff() {
    Client client = new Client(session);
    client.Connect(server);
    client.SendPacket (new Craft.Net.CreativeInventoryActionPacket(-1, new Craft.Net.ItemStack((short)19, (sbyte)1)));
    client.Disconnect ("Generic");
    System.Threading.Thread.Sleep(3000); 
}

接着：

while(true) { this.ConnectAndDoStuff() }

Answer 2

每次重新开始时在循环中创建实例。

while (true) {
    Client client = new Client(session);
    client.Connect(server);
    client.SendPacket (new Craft.Net.CreativeInventoryActionPacket(-1, new Craft.Net.ItemStack((short)19, (sbyte)1)));
    client.Disconnect ("Generic");

    System.Threading.Thread.Sleep(3000);
}

Answer 3

如果您只想重新创建client对象，只需删除类型定义

    Client client = new Client(session);
    client.Connect(server);
    while (true)
    {
        client.SendPacket (new Craft.Net.CreativeInventoryActionPacket(-1, new Craft.Net.ItemStack((short)19, (sbyte)1)));
        client.Disconnect ("Generic");
        System.Threading.Thread.Sleep(3000);
        client = new Client(session); 
        client.Connect(server);
    }