c# - 在运行时实现接口

Question

是否可以让已经编译的类在运行时实现某个接口，例如：

public interface ISomeInterface {
    void SomeMethod();
}

public class MyClass {
    // this is the class which i want to implement ISomeInterface at runtime
}

这可能吗，如果是，那怎么办？

Answer 1

差不多吧。您可以使用即兴界面。

https://github.com/ekonbenefits/impromptu-interface

来自https://github.com/ekonbenefits/impromptu-interface/wiki/UsageBasic的基本示例：

using ImpromptuInterface;

public interface ISimpleClassProps
{
  string Prop1 { get;  }
  long Prop2 { get; }
  Guid Prop3 { get; }
}

var tAnon = new {Prop1 = "Test", Prop2 = 42L, Prop3 = Guid.NewGuid()};
var tActsLike = tAnon.ActLike<ISimpleClassProps>();

Answer 2

您可以使用该Adapter模式使其看起来像是您实现了接口。这看起来有点像这样：

public interface ISomeInterface {
    void SomeMethod();
}

public class MyClass {
    // this is the class which i want to implement ISomeInterface at runtime
}

public SomeInterfaceAdapter{
    Myclass _adaptee;
    public SomeInterfaceAdapter(Myclass adaptee){
        _adaptee = adaptee;
    }
    void SomeMethod(){
        // forward calls to adaptee
        _adaptee.SomeOtherMethod();
    }
}

使用它看起来有点像这样：

Myclass baseobj = new Myclass();
ISomeInterface obj = new SomeInterfaceAdapter(baseobj);
obj.SomeMethod();