c#-4.0 - 将实例方法作为对象传递

Question

我正在尝试动态生成方法包装器。对于概念证明，我想要一个什么都不做的包装器。代码看起来像这样：

cSomeClassName testObject = new cSomeClassName();

dynamic wrapperObject = new ExpandoObject() as IDictionary<string, Object>;

foreach (var method in typeof(cSomeClassName).GetMethods())
{
    wrapperObject.Add(method.Name, 
                     (method.GetParameters()) => testObject.CallMethodWithParams(method.Name, method.GetParameters()));
}

打电话给

testObject.MethodName(params);

现在相当于

wrapperObject.MethodName(params);

我意识到这是一个非常糟糕的示例实现，但我不确定如何改进它。

Answer 1

经过大量陪审团操纵，我给你解决方案：

class cMethodExecutor
{
    private ArrayList m_ArgumentList;
    private Object m_CallObject;
    private string m_MethodName;

    public cMethodExecutor(Object iObject)
    {
        m_CallObject = iObject;
        m_ArgumentList = new ArrayList();
        m_MethodName = "";
    }

    public void SetMethodName(string iMethodName)
    {
        m_MethodName = iMethodName;
    }

    public void AddArgument(Object iArgument)
    {
        m_ArgumentList.Add(iArgument);
    }

    public object Execute()
    {
        return m_CallObject.GetType().GetMethod(m_MethodName).Invoke(m_CallObject, m_ArgumentList.ToArray());
    }
}


public delegate object ParamsFunc(params object[] iArgs);


//For now, we're going to just fall through to the original object:
IDictionary<string, object> obj = new ExpandoObject();

foreach (var method in typeof(cTestTarget).GetMethods())
{

    Console.WriteLine("Adding method: " + method.Name + "\n");

    obj.Add(method.Name, new ParamsFunc( inputList =>
    {
        cMethodExecutor newExecutor = new cMethodExecutor(iTestTarget);
        newExecutor.SetMethodName(method.Name);
        foreach (var param in inputList)
        {
            newExecutor.AddArgument(param);
        }

        return newExecutor.Execute();

    }));
}

iTestTarget 中存在的任何方法现在都存在于 obj 中，并分派到原始 iTestTarget。