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如何获取 svn 日志但排除分支添加信息？就像下面'svn log -v --stop-on-copy'的输出如何避免-r101？我正在尝试将其重定向到一个临时文件，然后只获取文件添加/修改/删除的详细信息。所以只需要没有分支创建修订的日志详细信息。

 svn log -v local/svn/demo/branches/Fix --stop-on-copy

 ------------------------------------------------------------------------
 r105 | user4 | 2013-05-24 16:27:11 -0400 (Fri, 24 May 2013) | 1 line
 Changed paths:
     M /branches/Fix/Code/Environment/RT/properties/build.properties

 ticket-9 
 ------------------------------------------------------------------------
 r104 | user4 | 2013-05-24 16:27:07 -0400 (Fri, 24 May 2013) | 1 line
 Changed paths:
     M /branches/Fix/Code/Environment/DEV/properties/build.properties

 ticket-7
 ------------------------------------------------------------------------
 r103 | user2 | 2013-05-24 15:27:25 -0400 (Fri, 24 May 2013) | 2 lines
 Changed paths:
     M /branches/Fix/Code/SharedApp/src/gov/illinois/ies/business/rules/ed/CorticonFinIncomeEntiyLoader.java

 ticket-2

 ------------------------------------------------------------------------
 r102 | user1 | 2013-05-24 15:19:54 -0400 (Fri, 24 May 2013) | 2 lines
 Changed paths:
    M /branches/Fix/Code/BEAN/Framework/ejbModule/gov/illinois/ies/business/rules/entities/fin/Income.java

 ticket-2

 ------------------------------------------------------------------------
 r101 | user4 | 2013-05-24 12:46:12 -0400 (Fri, 24 May 2013) | 3 lines
 Changed paths:
    A /branches/Fix (from /tags/2013-05-24T08:00:01.187-04:00_DEV_branch_WP_BUILD:100)

ticket-1

Re-creating the WP_Fix branch for 8AM tag

进一步更新： -- 现在我正在运行这个 :::

    svn log "$src_url" --stop-on-copy | grep -B 2 "$ticket" | grep "^r" | cut -d"r" -f2 | cut -d" " -f1 | sort -r

我的输出是：

   105
   104
   103
   102
   101

预期输出：

   105
   104
   103
   102
4

2 回答 2

0

有了awk你就可以使用regex range。像这样跳过你不想要的部分。

awk '/r101/,/^$/ {next}1' <(svn log -v --stop-on-copy)

这将从 r101 开始跳到下一个空白行。

更新：

如果您只需要文件列表，那么您可以执行以下操作 -

awk '($1 == "A" || $1 == "M" || $1 == "D") &&  NF==2' <(svn log -v --stop-on-copy)
于 2013-05-28T19:49:47.013 回答
0

选择一个合适的记录分隔符可以让事情变得简单。给定您的样本输入，这将产生您想要的输出。

awk -v RS='(^|\n)-+\n' '
    # ignore empty records
    /^$/ {next}
    # assume "A /branches/" is the the pattern for what you want to ignore
    /A \/branches\// {next}
    # print the revision number without its first character
    {print substr($1, 2)}
'

正则表达式的(^|\n)-+\n意思是：从数据的开头或换行符开始，匹配一个或多个连字符后跟一个换行符。

于 2013-05-28T22:05:33.600 回答