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我有一个 Mysql 架构(str),已创建(timestamp, current on create),我想运行一个查询以删除除最后 10 个之外的所有内容,我该怎么做?

4

4 回答 4

8
  DELETE FROM tablename 
    WHERE id NOT IN (
      SELECT id FROM tablename 
      ORDER BY created DESC 
      LIMIT 10);
于 2013-05-28T17:08:59.553 回答
0

你应该先收集 10 个 id

CREATE TEMPORARY TABLE ids_to_keep ENGINE=MyISAM
SELECT id FROM tablename WHERE 1=2;
INSERT INTO ids_to_keep
SELECT id FROM tablename ORDER BY created DESC LIMIT 10
ALTER TABLE ids_to_keep ADD PRIMARY KEYS (id);

从那里,尝试以下两种技术之一:

技巧#1:删除连接

DELETE A.* FROM tablename A
LEFT JOIN ids_to_keep B USING (id)
WHERE B.id IS NULL;
DROP TABLE ids_to_keep;

技巧#2:餐桌娱乐

CREATE TABLE tablename_new LIKE tablename;
ALTER TABLE tablename RENAME tablename_org;
INSERT INTO tablename_new
SELECT A.* FROM tablename_org A INNER JOIN ids_to_keep B USING (id);
DROP TABLE tablename_org;
ALTER TABLE tablename_new RENAME tablename;
DROP TABLE ids_to_keep;

试试看 !!!

于 2013-05-28T17:49:09.683 回答
0

您还可以使用一种方法的变体,使用自连接查找表中的第 N 个最大值。

DELETE FROM tablename WHERE created < (
SELECT created FROM tablename t1 WHERE
 (N - 1) = (SELECT COUNT( DISTINCT( created )
            FROM tablename t1
            WHERE t2.created > t1.created ) ) )

查询的内部部分为您提供了表中“created”的第 N 个最大值,您可以将其用作删除之前所有内容的参考。

于 2013-05-28T18:00:07.700 回答
0

好的,这是 9 行,而不是 10 行,但你明白了……

SELECT * FROM created;
+---------------------+
| t                   |
+---------------------+
| 2013-05-28 19:17:03 |
| 2013-05-28 19:17:06 |
| 2013-05-28 19:17:09 |
| 2013-05-28 19:17:11 |
| 2013-05-28 19:17:13 |
| 2013-05-28 19:17:16 |
| 2013-05-28 19:17:17 |
| 2013-05-28 19:17:19 |
| 2013-05-28 19:17:21 |
| 2013-05-28 19:17:23 |
| 2013-05-28 19:17:25 |
| 2013-05-28 19:17:27 |
| 2013-05-28 19:17:29 |
| 2013-05-28 19:17:31 |
| 2013-05-28 19:17:33 |
| 2013-05-28 19:17:35 |
| 2013-05-28 19:17:37 |
| 2013-05-28 19:17:39 |
+---------------------+
18 rows in set (0.00 sec)

DELETE a
  FROM created a
  JOIN
     (  SELECT x.*
          FROM created x
          JOIN created y
            ON y.t >= x.t
         GROUP
            BY x.t
        HAVING COUNT(*) = 10
     ) b
    ON b.t >= a.t;

SELECT * FROM created;
+---------------------+
| t                   |
+---------------------+
| 2013-05-28 19:17:23 |
| 2013-05-28 19:17:25 |
| 2013-05-28 19:17:27 |
| 2013-05-28 19:17:29 |
| 2013-05-28 19:17:31 |
| 2013-05-28 19:17:33 |
| 2013-05-28 19:17:35 |
| 2013-05-28 19:17:37 |
| 2013-05-28 19:17:39 |
+---------------------+
于 2013-05-28T18:17:34.413 回答